GATE CSE · Previous year papers · 2025

GATE CSE 2025 previous year paper · official paper and PYQ-pattern practice

15 PYQ-pattern questions modelled on the 2025 paper (which had 65) · 180 min

Every question here is freshly worded in the pattern of the 2025 paper — same topics, style and difficulty — not the original questions, which Shishya does not reproduce.

The original 2025 paper, as GATE 2025 organising institute (IIT Roorkee) published it

Full-length mock in the real pattern — 65 questions, 180 minutes →

Shishya's own practice questions, set out subject by subject like the real paper — not the original paper.

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15 PYQ-pattern questions modelled on the 2025 paper (which had 65) · instant scoring · topic-wise analysis. Sign up with Google, free, to attempt and track your progress.

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GATE CSE 2025 PYQ-pattern questions

Showing 10 of the 15 PYQ-pattern questions in this set — freshly worded in that year's pattern, not the original questions. Answers and solutions open under each question.

  1. Q1 · Verbal Aptitude

    Choose the word most similar in meaning to 'METICULOUS':

    • A. Careless
    • B. Precise
    • C. Lazy
    • D. Hasty
    Answer and solution

    Answer: B

    Meticulous means showing great attention to detail or being very careful and precise, so 'Precise' is the closest synonym.

  2. Q2 · Digital Logic

    What is the minimum number of 2-to-1 multiplexers required to implement a 4-to-1 multiplexer?

    • A. 2
    • B. 3
    • C. 4
    • D. 5
    Answer and solution

    Answer: B

    A 4-to-1 multiplexer can be constructed using three 2-to-1 multiplexers: two at the first level to select from pairs of inputs, and one at the second level to select between the outputs of the first two.

  3. Q3 · Computer Networks

    A network uses CSMA/CD with a transmission rate of 100 Mbps and a cable length of 2 km. If the propagation speed is 2 × 10⁸ m/s, what is the minimum frame size in bits to ensure collision detection?

    • A. 1000 bits
    • B. 2000 bits
    • C. 500 bits
    • D. 4000 bits
    Answer and solution

    Answer: B

    Round-trip time = (2 × 2000) / (2 × 10⁸) = 20 μs. Minimum frame transmission time = 20 μs. Frame size = 100 × 10⁶ × 20 × 10⁻⁶ = 2000 bits.

  4. Q4 · Digital Logic

    The minimal sum-of-products expression for the Boolean function F(A, B, C) = Σm(1, 3, 5, 7) is:

    • A. A
    • B. B
    • C. C
    • D. A + C
    Answer and solution

    Answer: C

    The minterms 1, 3, 5, 7 correspond to all combinations where C = 1. Using a K-map or inspection, the minimal expression simplifies to F = C.

  5. Q5 · Engineering Mathematics

    Let A be a 3×3 matrix with eigenvalues 2, 3, and 5. What is the determinant of the matrix (A - I), where I is the 3×3 identity matrix?

    • A. 6
    • B. 8
    • C. 10
    • D. 12
    Answer and solution

    Answer: B

    The eigenvalues of (A - I) are (2-1), (3-1), (5-1) = 1, 2, 4. The determinant equals the product of eigenvalues: 1×2×4 = 8.

  6. Q6 · Theory of Computation

    Which of the following languages is NOT context-free?

    • A. L = {a^n b^n c^m | n, m ≥ 0}
    • B. L = {a^n b^m c^n | n, m ≥ 0}
    • C. L = {a^n b^n c^n | n ≥ 0}
    • D. L = {w w^R | w ∈ {a, b}*}
    Answer and solution

    Answer: C

    L = {a^n b^n c^n | n ≥ 0} requires matching three counts simultaneously, which cannot be done by a single stack (PDA). It is context-sensitive but not context-free.

  7. Q7 · Databases

    Consider a relational schema R(A, B, C, D, E) with functional dependencies F = {A → B, BC → E, D → A}. Which of the following is a candidate key for R?

    • A. AD
    • B. CD
    • C. BD
    • D. AE
    Answer and solution

    Answer: B

    Starting with CD: C→(none directly), D→A (from D→A), then A→B, then BC→E. So CD→{A,B,C,D,E}, covering all attributes. Hence CD is a candidate key.

  8. Q8 · Computer Networks

    A network uses a subnet mask of 255.255.255.224. How many usable host addresses does each subnet support?

    • A. 30
    • B. 32
    • C. 62
    • D. 64
    Answer and solution

    Answer: A

    Subnet mask 255.255.255.224 is /27, giving 2^5=32 addresses per subnet. Usable host addresses = 32 - 2 = 30 (excluding network and broadcast addresses).

  9. Q9 · Computer Organization and Architecture

    A processor uses a 5-stage instruction pipeline with stages: Fetch (F), Decode (D), Execute (E), Memory (M), and Write-back (W). Each stage takes exactly one clock cycle. Consider executing 8 independent instructions. If the pipeline operates without any hazards or stalls, how many clock cycles are required to complete the execution of all 8 instructions?

    • A. 8
    • B. 12
    • C. 40
    • D. 13
    Answer and solution

    Answer: B

    In a 5-stage pipeline, the first instruction takes 5 cycles to complete. After that, one instruction completes every cycle. Total cycles = 5 + (8-1) = 12 cycles.

  10. Q10 · Verbal Aptitude

    The manager declared that the project was completed _______ schedule, which pleased the stakeholders. Choose the option that correctly fills in the blank.

    • A. ahead of
    • B. ahead to
    • C. ahead from
    • D. ahead off
    Answer and solution

    Answer: A

    'Ahead of' is the correct idiomatic expression used when comparing time or position with respect to a deadline or standard.

Breakdown by subject

  • General Aptitude

    3 questions

  • Computer Science and Information Technology

    12 questions

GATE CSE 2025 previous year paper — frequently asked questions

Where can I solve the GATE CSE 2025 previous year paper (PYQ) free online?
At https://shishya.in/exams/GATE_CSE/pyq/2025 you can solve GATE CSE 15 PYQ-pattern questions modelled on the 2025 paper free. Shishya does not reproduce the original paper: every question is freshly worded in that year's pattern — same topics, style and difficulty, new wording and numbers, and this set holds 15 questions, not the whole paper. They run as a timed mock with instant scoring, step-by-step solutions and topic-wise weak-area analysis. No fee and no coaching enrolment needed. The original 2025 paper is published by GATE 2025 organising institute (IIT Roorkee): https://gate2025.iitr.ac.in/doc/2025/2025_QP/CS1.pdf
Are these the actual GATE CSE 2025 paper questions?
No. They are PYQ-pattern questions modelled on the GATE CSE 2025 paper — freshly worded practice questions in the same pattern, not the original questions, which Shishya does not reproduce. This set holds 15 questions. The original 2025 paper is published by GATE 2025 organising institute (IIT Roorkee): https://gate2025.iitr.ac.in/doc/2025/2025_QP/CS1.pdf For a whole paper in one sitting, Shishya has a free full-length mock in the real pattern (65 questions, 180 minutes): the "Full-Length Mock (Real Pattern)" tile at https://shishya.in/exams/GATE_CSE
Do these GATE CSE 2025 pattern questions come with solutions and analysis?
Yes — every question carries a worked solution, and on submitting you get an instant score with a topic-wise breakdown showing exactly which areas to revise. Wrong answers are auto-collected into a free Mistake Notebook for one-tap re-practice until cleared.
Are previous year papers enough to crack GATE CSE?
Previous-year papers are the best signal of what the exam actually tests, but they work best with targeted practice and a plan. On Shishya (all free): solve PYQ-pattern sets year-wise, drill weak topics via the Mistake Notebook, follow a day-by-day plan from the Personal Coach at https://shishya.in/coach and sit the Sunday live test at https://shishya.in/live-test to see where you stand nationally.