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NCERT Class 10 Science Electricity: In-text questions (page 192) Solutions

AI-written, checked on 23 Oct 2026

Solutions written by Shishya, checked — not the board's official answers

Step-by-step working for every question of In-text questions (page 192) in NCERT's Class 10 Science book, chapter “Electricity”, written by Shishya. Each question is in our own short words; open the NCERT chapter for the exact wording and figures.

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How these were checked: the solutions were drafted with AI and then read and corrected on 23 Oct 2026. Every numerical final answer is recomputed from the question's own numbers by a calculator check that runs before each release; proofs and explanations were read, not machine-checked. The NCERT textbook is the authority — if something here disagrees with it, follow the book.

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  1. In-text (page 192) Q1

    What decides the rate at which energy is delivered by a current?

    1. The rate at which electrical energy is delivered by a current is called electric power.
      why?

      Electric power P = VI = I²R = V²/R; energy = power × time, and 1 kWh = 3.6 × 10⁶ J.

    2. This rate depends on the current flowing through the conductor and the potential difference across it.
    3. Mathematically, power P is the product of current I and voltage V, so P = VI.
      why?

      Electric power P = VI = I²R = V²/R; energy = power × time, and 1 kWh = 3.6 × 10⁶ J.

    4. Using Ohm's law (V = IR), we can also express power as P = I²R or P = V²/R.
      why?

      Electric power P = VI = I²R = V²/R; energy = power × time, and 1 kWh = 3.6 × 10⁶ J.

    5. Therefore, the rate of energy delivery is decided by the current, the voltage, and the resistance of the circuit.

    Answer: The rate at which energy is delivered by a current is decided by the current (I) and the potential difference (V), given by P = VI.

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  2. In-text (page 192) Q2

    An electric motor takes 5 A from a 220 V line. Find its power and the energy used in 2 h.

    1. Given current I = 5 A and voltage V = 220 V.
    2. Power P = V × I = 220 × 5 = 1100 W.
      why?

      Electric power P = VI = I²R = V²/R; energy = power × time, and 1 kWh = 3.6 × 10⁶ J.

    3. Time t = 2 h = 2 × 3600 s = 7200 s.
    4. Energy E = P × t = 1100 × 7200 = 7920000 J.
    5. Energy E = 7.92 × 10⁶ J.

    Answer: Power = 1100 W; Energy = 7.92 × 10⁶ J

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