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NCERT Class 10 Science Chemical Reactions and Equations: In-text questions (page 13) Solutions

AI-written, checked on 23 Oct 2026

Solutions written by Shishya, checked — not the board's official answers

Step-by-step working for every question of In-text questions (page 13) in NCERT's Class 10 Science book, chapter “Chemical Reactions and Equations”, written by Shishya. Each question is in our own short words; open the NCERT chapter for the exact wording and figures.

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  1. In-text (page 13) Q1

    Why does the colour of copper sulphate solution change when an iron nail is dipped in it?

    1. Iron is more reactive than copper, so it displaces copper from the copper sulphate solution.
      why?

      A more reactive metal displaces a less reactive metal from a solution of its salt (reactivity series); a less reactive metal cannot displace a more reactive one.

    2. The iron nail reacts with copper sulphate to form iron sulphate and copper metal.
    3. The copper metal deposits on the surface of the iron nail.
    4. The solution now contains iron sulphate, which is pale green in colour.
    5. The original blue colour of copper sulphate fades as the copper ions are removed from the solution.

    Answer: The colour changes from blue to pale green because iron displaces copper, forming iron sulphate in the solution.

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  2. In-text (page 13) Q2

    Give an example of a double displacement reaction other than the one in Activity 1.10.

    1. In a double displacement reaction two compounds exchange their ions to form two new compounds.
    2. Activity 1.10 uses sodium sulphate and barium chloride, so take a different pair: silver nitrate and sodium chloride solutions.
    3. When they are mixed, silver ions (Ag⁺) and chloride ions (Cl⁻) join to form a white precipitate of silver chloride, while sodium nitrate stays in solution.
    4. AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq).

    Answer: AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq) (another example: Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s) + 2KNO₃(aq))

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  3. In-text (page 13) Q3

    Identify the substances oxidised and reduced: (i) 4Na(s) + O₂(g) → 2Na₂O(s) (ii) CuO(s) + H₂(g) → Cu(s) + H₂O(l).

    1. (i) In the reaction 4Na(s) + O₂(g) → 2Na₂O(s), sodium (Na) gains oxygen.
    2. Sodium is therefore oxidised.
      why?

      Oxidation is gain of oxygen (or loss of hydrogen); reduction is loss of oxygen (or gain of hydrogen). In a redox reaction one substance is oxidised while another is reduced.

    3. Oxygen combines with sodium; it is the substance that gets reduced (it is the oxidising agent).
      why?

      Oxidation is gain of oxygen (or loss of hydrogen); reduction is loss of oxygen (or gain of hydrogen). In a redox reaction one substance is oxidised while another is reduced.

    4. Oxygen is reduced in this reaction.
      why?

      Oxidation is gain of oxygen (or loss of hydrogen); reduction is loss of oxygen (or gain of hydrogen). In a redox reaction one substance is oxidised while another is reduced.

    5. (ii) In the reaction CuO(s) + H₂(g) → Cu(s) + H₂O(l), copper oxide (CuO) loses oxygen.
    6. Copper oxide is therefore reduced.
      why?

      Oxidation is gain of oxygen (or loss of hydrogen); reduction is loss of oxygen (or gain of hydrogen). In a redox reaction one substance is oxidised while another is reduced.

    7. Hydrogen (H₂) gains oxygen to form water.
    8. Hydrogen is therefore oxidised.
      why?

      Oxidation is gain of oxygen (or loss of hydrogen); reduction is loss of oxygen (or gain of hydrogen). In a redox reaction one substance is oxidised while another is reduced.

    Answer: (i) Oxidised: Na, Reduced: O₂; (ii) Oxidised: H₂, Reduced: CuO

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