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NCERT Class 10 Mathematics Exercise 10.1 Solutions: Circles

AI-written, checked on 23 Oct 2026

Solutions written by Shishya, checked — not the board's official answers

Step-by-step working for every question of Exercise 10.1 in NCERT's Class 10 Mathematics book, chapter “Circles”, written by Shishya. Each question is in our own short words; open the NCERT chapter for the exact wording and figures.

How these were checked: the solutions were drafted with AI and then read and corrected on 23 Oct 2026. Every numerical final answer is recomputed from the question's own numbers by a calculator check that runs before each release; proofs and explanations were read, not machine-checked. The NCERT textbook is the authority — if something here disagrees with it, follow the book.

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  1. Ex 10.1 Q1

    How many tangents can a circle have?

    1. A tangent to a circle is a line that touches the circle at exactly one point.
    2. Since a circle is a closed curve, there are infinitely many points on its circumference.
    3. At each of these infinitely many points, exactly one tangent can be drawn.
    4. Therefore, a circle can have infinitely many tangents.

    Answer: A circle can have infinitely many tangents.

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  2. Ex 10.1 Q2

    Fill the blanks: (i) a tangent meets a circle in … point(s) (ii) a line meeting a circle in two points is a … (iii) a circle can have at most … parallel tangents (iv) the common point of a tangent and the circle is the …

    1. (i) A tangent touches the circle at exactly one location, so it meets the circle in one point.
    2. (ii) A line that intersects the circle at two distinct points is called a secant.
    3. (iii) A circle can have two parallel tangents, one on each side of the diameter.
    4. (iv) The specific point where the tangent line touches the circle is known as the point of contact.

    Answer: (i) one; (ii) secant; (iii) two; (iv) point of contact

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  3. Ex 10.1 Q3

    A tangent PQ at P of a circle of radius 5 cm meets a line through the centre O at Q, with OQ = 12 cm. Find PQ: (A) 12 cm (B) 13 cm (C) 8.5 cm (D) √119 cm.

    1. Since PQ is a tangent to the circle at point P, the radius OP is perpendicular to the tangent PQ.
      why?

      The tangent at any point of a circle is perpendicular to the radius through the point of contact.

    2. Therefore, angle OPQ is 90 degrees, making triangle OPQ a right-angled triangle.
    3. Given that the radius OP is 5 cm and the distance OQ is 12 cm.
    4. Apply the Pythagoras theorem to triangle OPQ: OP² + PQ² = OQ².
      why?

      In a right-angled triangle, (hypotenuse)² = (one side)² + (other side)² (Baudhāyana–Pythagoras theorem). The hypotenuse is the side opposite the right angle and is the longest side.

    5. Substitute the known values into the equation: 5² + PQ² = 12².
      why?

      Putting the known values in place of the letters turns the formula or equation into plain arithmetic — the letters stood for exactly these values.

    6. Calculate the squares: 25 + PQ² = 144.
    7. Rearrange the equation to solve for PQ²: PQ² = 144 − 25.
    8. Compute the difference: PQ² = 119.
    9. Take the square root of both sides to find the length of PQ: PQ = √119 cm.
      why?

      If two non-negative quantities are equal, their square roots are equal. A square has two roots, + and −; a length or a count cannot be negative, so the negative root is dropped there.

    10. Compare this result with the given options to identify the correct choice.

    Answer: (D) √119 cm

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  4. Ex 10.1 Q4

    Draw a circle and two lines parallel to a given line so that one is a tangent and the other a secant.

    1. Draw a circle with centre O and radius 5 cm.
    2. Draw a line l outside the circle such that its distance from O is greater than 5 cm.
    3. From O, draw a perpendicular to line l meeting it at point P.
    4. Draw a line m parallel to l passing through P; this line is at a distance equal to the radius from O.
    5. Since the distance from O to m equals the radius, m touches the circle at exactly one point, making it a tangent.
      why?

      The tangent at any point of a circle is perpendicular to the radius through the point of contact.

    6. Draw a line n parallel to l on the other side of O such that its distance from O is less than 5 cm.
    7. Since the distance from O to n is less than the radius, line n cuts the circle at two distinct points, making it a secant.
    8. Thus, m is a tangent and n is a secant, both parallel to the given line l.

    Answer: A circle is drawn with a tangent line and a secant line, both parallel to a given line.

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Other exercises in this chapter

← Circles: notes, practice and all exercises

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