RRB NTPC · Previous year papers · 2023

RRB NTPC 2023 previous year paper practice · PYQ-pattern set

14 PYQ-pattern questions modelled on the 2023 paper (which had 100) · 90 min

Every question here is freshly worded in the pattern of the 2023 paper — same topics, style and difficulty — not the original questions, which Shishya does not reproduce.

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Shishya's own practice questions, set out subject by subject like the real paper — not the original paper.

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RRB NTPC 2023 PYQ-pattern questions

Showing 10 of the 14 PYQ-pattern questions in this set — freshly worded in that year's pattern, not the original questions. Answers and solutions open under each question.

  1. Q1 · Time and Work

    A can complete a work in 12 days and B can complete the same work in 18 days. If they work together for 4 days, what fraction of the work remains?

    • A. 1/3
    • B. 2/5
    • C. 1/9
    • D. 4/9
    Answer and solution

    Answer: D

    A's rate 1/12, B's rate 1/18; sum = 5/36 per day. Over 4 days they complete 20/36 = 5/9. Remaining work = 1 - 5/9 = 4/9.

  2. Q2 · Percentage

    A shopkeeper marks his goods 25% above the cost price and gives a discount of 10%. What is his profit percentage?

    • A. 10%
    • B. 12.5%
    • C. 15%
    • D. 17.5%
    Answer and solution

    Answer: B

    Let CP = 100. Marked price = 125. After 10% discount, SP = 125 × 0.9 = 112.5. Profit = 112.5 - 100 = 12.5, so profit% = 12.5%.

  3. Q3 · Completion of Number and Alphabetical Series

    Find the missing number in the series: 7, 14, 28, 56, ?

    • A. 84
    • B. 96
    • C. 112
    • D. 120
    Answer and solution

    Answer: C

    Each term is obtained by multiplying the previous term by 2. Thus, 56 × 2 = 112.

  4. Q4 · LCM and HCF

    The HCF of two numbers is 15 and their LCM is 300. If one of the numbers is 60, what is the other number?

    • A. 75
    • B. 90
    • C. 120
    • D. 150
    Answer and solution

    Answer: A

    Using the formula: Product of two numbers = HCF × LCM, so the other number = (15 × 300) ÷ 60 = 75.

  5. Q5 · Time, Distance and Speed

    A train 150 meters long crosses a platform 250 meters long in 20 seconds. What is the speed of the train in km/hr?

    • A. 54 km/hr
    • B. 60 km/hr
    • C. 72 km/hr
    • D. 80 km/hr
    Answer and solution

    Answer: C

    Total distance = 150 + 250 = 400 meters. Speed = 400/20 = 20 m/s = 20 × 18/5 = 72 km/hr.

  6. Q6 · Simple and Compound Interest

    Find the compound interest on ₹5,000 at 10% per annum for 2 years, compounded annually.

    • A. ₹1,000
    • B. ₹1,050
    • C. ₹1,100
    • D. ₹1,200
    Answer and solution

    Answer: B

    Amount = P(1 + R/100)^T = 5000(1.1)² = 5000 × 1.21 = ₹6,050. Compound Interest = 6,050 - 5,000 = ₹1,050.

  7. Q7 · Completion of Number and Alphabetical Series

    Find the missing number in the series: 3, 7, 15, 31, ?, 127

    • A. 59
    • B. 61
    • C. 63
    • D. 65
    Answer and solution

    Answer: C

    Pattern: Each term = (Previous term × 2) + 1. So, 31 × 2 + 1 = 63.

  8. Q8 · Analogies

    Complete the analogy: 16 : 256 :: 12 : ?

    • A. 120
    • B. 144
    • C. 156
    • D. 168
    Answer and solution

    Answer: B

    The pattern is number × itself = result. 16 × 16 = 256, similarly 12 × 12 = 144.

  9. Q9 · Percentage

    If a man's salary is increased by 20% and then decreased by 20%, what is the net percentage change in his salary?

    • A. No change
    • B. 4% decrease
    • C. 4% increase
    • D. 2% decrease
    Answer and solution

    Answer: B

    Let original salary be 100. After 20% increase: 120. After 20% decrease on 120: 120 - 24 = 96. Net change = 96 - 100 = -4, which is 4% decrease.

  10. Q10 · Simple and Compound Interest

    The difference between compound interest and simple interest on a sum for 2 years at 8% per annum is ₹64. Find the principal amount.

    • A. ₹8,000
    • B. ₹10,000
    • C. ₹12,000
    • D. ₹9,500
    Answer and solution

    Answer: B

    Difference = P(R/100)² for 2 years. So 64 = P × (8/100)² = P × 64/10000. Therefore P = ₹10,000.

Breakdown by subject

  • Mathematics

    8 questions

  • General Intelligence and Reasoning

    6 questions

RRB NTPC 2023 previous year paper — frequently asked questions

Where can I solve the RRB NTPC 2023 previous year paper (PYQ) free online?
At https://shishya.in/exams/RRB_NTPC/pyq/2023 you can solve RRB NTPC 14 PYQ-pattern questions modelled on the 2023 paper free. Shishya does not reproduce the original paper: every question is freshly worded in that year's pattern — same topics, style and difficulty, new wording and numbers, and this set holds 14 questions, not the whole paper. They run as a timed mock with instant scoring, step-by-step solutions and topic-wise weak-area analysis. No fee and no coaching enrolment needed.
Are these the actual RRB NTPC 2023 paper questions?
No. They are PYQ-pattern questions modelled on the RRB NTPC 2023 paper — freshly worded practice questions in the same pattern, not the original questions, which Shishya does not reproduce. This set holds 14 questions. For a whole paper in one sitting, Shishya has a free full-length mock in the real pattern (100 questions, 90 minutes): the "Full-Length Mock (Real Pattern)" tile at https://shishya.in/exams/RRB_NTPC
Do these RRB NTPC 2023 pattern questions come with solutions and analysis?
Yes — every question carries a worked solution, and on submitting you get an instant score with a topic-wise breakdown showing exactly which areas to revise. Wrong answers are auto-collected into a free Mistake Notebook for one-tap re-practice until cleared.
Are previous year papers enough to crack RRB NTPC?
Previous-year papers are the best signal of what the exam actually tests, but they work best with targeted practice and a plan. On Shishya (all free): solve PYQ-pattern sets year-wise, drill weak topics via the Mistake Notebook, follow a day-by-day plan from the Personal Coach at https://shishya.in/coach and sit the Sunday All-India Live Test at https://shishya.in/live-test to see where you stand nationally.