RRB NTPC · Previous year papers · 2023
RRB NTPC 2023 previous year paper practice · PYQ-pattern set
14 PYQ-pattern questions modelled on the 2023 paper (which had 100) · 90 min
Every question here is freshly worded in the pattern of the 2023 paper — same topics, style and difficulty — not the original questions, which Shishya does not reproduce.
Shishya's own practice questions, set out subject by subject like the real paper — not the original paper.
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Showing 10 of the 14 PYQ-pattern questions in this set — freshly worded in that year's pattern, not the original questions. Answers and solutions open under each question.
Q1 · Time and Work
A can complete a work in 12 days and B can complete the same work in 18 days. If they work together for 4 days, what fraction of the work remains?
- A. 1/3
- B. 2/5
- C. 1/9
- D. 4/9
Answer and solution
Answer: D
A's rate 1/12, B's rate 1/18; sum = 5/36 per day. Over 4 days they complete 20/36 = 5/9. Remaining work = 1 - 5/9 = 4/9.
Q2 · Percentage
A shopkeeper marks his goods 25% above the cost price and gives a discount of 10%. What is his profit percentage?
- A. 10%
- B. 12.5%
- C. 15%
- D. 17.5%
Answer and solution
Answer: B
Let CP = 100. Marked price = 125. After 10% discount, SP = 125 × 0.9 = 112.5. Profit = 112.5 - 100 = 12.5, so profit% = 12.5%.
Q3 · Completion of Number and Alphabetical Series
Find the missing number in the series: 7, 14, 28, 56, ?
- A. 84
- B. 96
- C. 112
- D. 120
Answer and solution
Answer: C
Each term is obtained by multiplying the previous term by 2. Thus, 56 × 2 = 112.
Q4 · LCM and HCF
The HCF of two numbers is 15 and their LCM is 300. If one of the numbers is 60, what is the other number?
- A. 75
- B. 90
- C. 120
- D. 150
Answer and solution
Answer: A
Using the formula: Product of two numbers = HCF × LCM, so the other number = (15 × 300) ÷ 60 = 75.
Q5 · Time, Distance and Speed
A train 150 meters long crosses a platform 250 meters long in 20 seconds. What is the speed of the train in km/hr?
- A. 54 km/hr
- B. 60 km/hr
- C. 72 km/hr
- D. 80 km/hr
Answer and solution
Answer: C
Total distance = 150 + 250 = 400 meters. Speed = 400/20 = 20 m/s = 20 × 18/5 = 72 km/hr.
Q6 · Simple and Compound Interest
Find the compound interest on ₹5,000 at 10% per annum for 2 years, compounded annually.
- A. ₹1,000
- B. ₹1,050
- C. ₹1,100
- D. ₹1,200
Answer and solution
Answer: B
Amount = P(1 + R/100)^T = 5000(1.1)² = 5000 × 1.21 = ₹6,050. Compound Interest = 6,050 - 5,000 = ₹1,050.
Q7 · Completion of Number and Alphabetical Series
Find the missing number in the series: 3, 7, 15, 31, ?, 127
- A. 59
- B. 61
- C. 63
- D. 65
Answer and solution
Answer: C
Pattern: Each term = (Previous term × 2) + 1. So, 31 × 2 + 1 = 63.
Q8 · Analogies
Complete the analogy: 16 : 256 :: 12 : ?
- A. 120
- B. 144
- C. 156
- D. 168
Answer and solution
Answer: B
The pattern is number × itself = result. 16 × 16 = 256, similarly 12 × 12 = 144.
Q9 · Percentage
If a man's salary is increased by 20% and then decreased by 20%, what is the net percentage change in his salary?
- A. No change
- B. 4% decrease
- C. 4% increase
- D. 2% decrease
Answer and solution
Answer: B
Let original salary be 100. After 20% increase: 120. After 20% decrease on 120: 120 - 24 = 96. Net change = 96 - 100 = -4, which is 4% decrease.
Q10 · Simple and Compound Interest
The difference between compound interest and simple interest on a sum for 2 years at 8% per annum is ₹64. Find the principal amount.
- A. ₹8,000
- B. ₹10,000
- C. ₹12,000
- D. ₹9,500
Answer and solution
Answer: B
Difference = P(R/100)² for 2 years. So 64 = P × (8/100)² = P × 64/10000. Therefore P = ₹10,000.
Breakdown by subject
Mathematics
8 questions
General Intelligence and Reasoning
6 questions