RRB NTPC · Previous year papers · 2021
RRB NTPC 2021 previous year paper practice · PYQ-pattern set
14 PYQ-pattern questions modelled on the 2021 paper (which had 100) · 90 min
Every question here is freshly worded in the pattern of the 2021 paper — same topics, style and difficulty — not the original questions, which Shishya does not reproduce.
Shishya's own practice questions, set out subject by subject like the real paper — not the original paper.
Solve these 14 2021-pattern questions as a timed mock — free
14 PYQ-pattern questions modelled on the 2021 paper (which had 100) · instant scoring · topic-wise analysis. Sign up with Google, free, to attempt and track your progress.
Stuck on a question from this set?
Ask Shishya — your free AI tutor — to explain any RRB NTPC 2021-pattern question, concept, or shortcut, step by step, in your language.
Ask Shishya about this set →RRB NTPC 2021 PYQ-pattern questions
Showing 10 of the 14 PYQ-pattern questions in this set — freshly worded in that year's pattern, not the original questions. Answers and solutions open under each question.
Q1 · Mensuration
A rectangular field has a length of 60 m and breadth of 40 m. What is the cost of fencing it at ₹18 per meter?
- A. ₹3,200
- B. ₹3,400
- C. ₹3,600
- D. ₹4,000
Answer and solution
Answer: C
Perimeter of rectangle = 2(length + breadth) = 2(60 + 40) = 200 m. Cost of fencing = 200 × 18 = ₹3,600.
Q2 · LCM and HCF
Find the smallest number which when divided by 8, 12, and 16 leaves a remainder of 5 in each case.
- A. 48
- B. 53
- C. 96
- D. 101
Answer and solution
Answer: B
LCM of 8, 12, and 16 is 48. The required number = LCM + remainder = 48 + 5 = 53.
Q3 · Elementary Statistics
The mean of 8 numbers is 42. If one number 56 is excluded, what is the mean of the remaining 7 numbers?
- A. 38
- B. 40
- C. 41
- D. 44
Answer and solution
Answer: B
Total sum of 8 numbers = 8 × 42 = 336. After excluding 56, sum = 336 - 56 = 280. New mean = 280/7 = 40.
Q4 · Simple and Compound Interest
The difference between compound interest and simple interest on a certain sum for 2 years at 8% per annum is ₹128. What is the principal amount?
- A. ₹18,000
- B. ₹20,000
- C. ₹22,500
- D. ₹25,000
Answer and solution
Answer: B
The difference between CI and SI for 2 years = P(R/100)². So 128 = P × (8/100)², which gives 128 = P × 64/10000. Therefore, P = 128 × 10000/64 = ₹20,000.
Q5 · Percentage
A man's salary was reduced by 20%. By what percentage must his reduced salary be increased to restore it to the original amount?
- A. 20%
- B. 25%
- C. 30%
- D. 40%
Answer and solution
Answer: B
If original salary is 100, reduced salary is 80. To restore: (20/80) × 100 = 25% increase is needed.
Q6 · LCM and HCF
The least number which when divided by 8, 12 and 16 leaves a remainder of 3 in each case is:
- A. 48
- B. 51
- C. 45
- D. 99
Answer and solution
Answer: B
LCM of 8, 12, and 16 is 48. The required number = 48 + 3 = 51.
Q7 · Time, Distance and Speed
A person covers a distance of 240 km partly by train at 60 km/hr and partly by car at 80 km/hr. If the total journey takes 3.5 hours, what distance did he travel by train?
- A. 120 km
- B. 140 km
- C. 160 km
- D. 100 km
Answer and solution
Answer: A
Let train distance be x km, car distance 240-x. Time: x/60 + (240-x)/80 = 3.5. Multiply by 240: 4x + 3(240-x) = 840, giving 4x + 720 - 3x = 840, so x = 120 km.
Q8 · Geometry and Trigonometry
The area of a circle is 154 cm². What is its radius? (Use π = 22/7)
- A. 5 cm
- B. 6 cm
- C. 7 cm
- D. 8 cm
Answer and solution
Answer: C
Area = πr² → 154 = (22/7) × r² → r² = (154 × 7)/22 = 49 → r = 7 cm.
Q9 · Profit and Loss
A trader sold an article at a loss of 15%. If he had sold it for ₹340 more, he would have gained 10%. What was the cost price of the article?
- A. ₹1,200
- B. ₹1,360
- C. ₹1,400
- D. ₹1,500
Answer and solution
Answer: B
The difference between 15% loss and 10% gain = 25% of CP = ₹340. So CP = 340 × 100/25 = ₹1,360.
Q10 · Decimals and Fractions
What is the value of (0.75 × 0.48) ÷ (1.5 × 0.12)?
- A. 2
- B. 1.5
- C. 2.5
- D. 3
Answer and solution
Answer: A
Numerator = 0.75 × 0.48 = 0.36. Denominator = 1.5 × 0.12 = 0.18. Result = 0.36 ÷ 0.18 = 2.
Breakdown by subject
Mathematics
13 questions
General Intelligence and Reasoning
1 questions