NSTSE · Previous year papers · 2023
NSTSE 2023 previous year paper practice · PYQ-pattern set
20 PYQ-pattern questions modelled on the 2023 paper (which had 60) · 60 min
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Showing 10 of the 20 PYQ-pattern questions in this set — freshly worded in that year's pattern, not the original questions. Answers and solutions open under each question.
Q1 · Linear Equations in Two Variables
The pair of linear equations 2x + 5y = 8 and 4x + 10y = 16 has:
- A. A unique solution
- B. Infinitely many solutions
- C. No solution
- D. Exactly two solutions
Answer and solution
Answer: B
The second equation is exactly 2 times the first equation, meaning they represent the same line. Hence the system has infinitely many solutions.
Q2 · Circles
Two tangents PA and PB are drawn to a circle with center O from an external point P. If ∠APB = 50°, then ∠AOB equals:
- A. 130°
- B. 100°
- C. 120°
- D. 140°
Answer and solution
Answer: A
In quadrilateral OAPB, sum of angles = 360°. Since ∠OAP = ∠OBP = 90° (radius ⊥ tangent), we have 90° + 90° + 50° + ∠AOB = 360°, so ∠AOB = 130°.
Q3 · Mensuration
A rectangular field has length 25 m and breadth 16 m. What is the area of the field?
- A. 400 m²
- B. 350 m²
- C. 450 m²
- D. 425 m²
Answer and solution
Answer: A
The area of a rectangle is length × breadth = 25 × 16 = 400 m².
Q4 · Gravitation
The value of acceleration due to gravity on the surface of Earth is approximately:
- A. 8.8 m/s²
- B. 9.8 m/s²
- C. 10.8 m/s²
- D. 11.8 m/s²
Answer and solution
Answer: B
The standard value of acceleration due to gravity on Earth's surface is approximately 9.8 m/s².
Q5 · Light — Reflection and Refraction
A concave mirror forms a real image of height 4 cm when the object of height 2 cm is placed 15 cm in front of it. What is the focal length of the mirror?
- A. 5 cm
- B. 10 cm
- C. 15 cm
- D. 20 cm
Answer and solution
Answer: B
Magnification m = −v/u = h'/h = 4/2 = 2 (taking magnitude). Since real image, v = −30 cm. Using 1/f = 1/v + 1/u: 1/f = 1/(−30) + 1/(−15) = −1/10, so f = −10 cm (magnitude 10 cm).
Q6 · Atoms and Molecules
How many moles of calcium carbonate (CaCO₃) are present in 25 g of it? (Given: Ca=40, C=12, O=16)
- A. 0.15 moles
- B. 0.20 moles
- C. 0.25 moles
- D. 0.30 moles
Answer and solution
Answer: C
Molar mass of CaCO₃ = 40+12+(16×3) = 100 g/mol. Number of moles = 25/100 = 0.25 moles.
Q7 · Acids, Bases and Salts
A solution changes the color of red litmus to blue. What is the nature of this solution?
- A. Acidic
- B. Basic
- C. Neutral
- D. Cannot be determined
Answer and solution
Answer: B
Red litmus turns blue in a basic (alkaline) solution, indicating the presence of a base.
Q8 · Tissues
Which type of tissue is responsible for the movement of our body parts?
- A. Epithelial tissue
- B. Connective tissue
- C. Muscular tissue
- D. Nervous tissue
Answer and solution
Answer: C
Muscular tissue is responsible for movement in the body as muscle cells have the ability to contract and relax.
Q9 · Control and Coordination
Which hormone is responsible for regulating blood sugar levels by promoting the uptake of glucose into cells?
- A. Glucagon
- B. Adrenaline
- C. Insulin
- D. Thyroxine
Answer and solution
Answer: C
Insulin, produced by the pancreas, lowers blood glucose levels by facilitating cellular uptake of glucose and promoting its storage as glycogen.
Q10 · Life Processes
During aerobic respiration in mitochondria, the maximum number of ATP molecules are produced in which stage?
- A. Glycolysis
- B. Krebs cycle
- C. Electron transport chain
- D. Fermentation
Answer and solution
Answer: C
The electron transport chain produces approximately 34 ATP molecules, which is the maximum among all stages of aerobic respiration.
Breakdown by subject
Mathematics
6 questions
Physics
4 questions
Chemistry
4 questions
Biology
4 questions
General Questions and Reasoning
2 questions