MHT-CET · Physics

More Maharashtra government exams →

Kinetic Theory of Gases (Class 11 — ~20% weight)

Ideal gas equation, RMS speed, degrees of freedom, mean free path.

Test yourself on Kinetic Theory of Gases (Class 11 — ~20% weight)

Practice questions for MHT-CET on this topic with instant answers — no signup.

Take the quick quiz →

Study notes are still being prepared.

Don't wait — Shishya can teach you this topic right now, on demand.

Ask Shishya to teach this →

Need more? Ask Shishya

Shishya is your personal tutor for this topic. Pick a starter or open a free chat.

Open Shishya tutor →

Practice this topic

Take a full mock →
  • Q1 · Kinetic Theory of Gases (Class 11 — ~20% weight) · EASY

    At a given temperature, the root mean square (rms) speed of oxygen molecules (O₂, molecular mass = 32 u) is 400 m/s. What will be the rms speed of hydrogen molecules (H₂, molecular mass = 2 u) at the same temperature?

  • Q2 · Kinetic Theory of Gases (Class 11 — ~20% weight) · MEDIUM

    A monoatomic ideal gas and a diatomic ideal gas are at the same temperature. If the rms speed of molecules in the monoatomic gas is 500 m/s and both gases have the same molar mass, what is the rms speed of molecules in the diatomic gas?

  • Q3 · Kinetic Theory of Gases (Class 11 — ~20% weight) · HARD

    At temperature T, the mean free path of molecules of a gas is λ. If the pressure is doubled and temperature is increased to 2T while keeping the volume constant, what will be the new mean free path?

  • Q4 · Kinetic Theory of Gases (Class 11 — ~20% weight) · HARD

    An ideal gas is enclosed in a container at 27°C. If the temperature is increased such that the root mean square velocity of the molecules becomes twice the initial value, the final temperature of the gas is:

Ask Shishya to explain these →