MHT-CET · Periodic Classification (Class 11 — ~20% weight) · Quiz
Periodic Classification (Class 11 — ~20% weight) — quick quiz
3 MHT-CET-pattern questions on Periodic Classification (Class 11 — ~20% weight). Instant scoring and solutions, no signup — see where you stand in a few minutes.
Question 1 of 3
HardConsider the following elements: F (fluorine), Cl (chlorine), O (oxygen), and S (sulfur). If the electron affinity values (in kJ/mol) are approximately: Cl = 349, O = 141, S = 200, and F = 328, which statement correctly explains why fluorine has a lower electron affinity than chlorine despite being more electronegative?