MHT-CET 2022 previous year paper practice · PYQ-pattern set

MHT-CET 2022 PYQ-pattern questions

Showing 10 of the 19 PYQ-pattern questions in this set — freshly worded in that year's pattern, not the original questions. Answers and solutions open under each question.

1. Q1 · Work, Energy and Power (Class 11 — ~20% weight)

   A body of mass 3 kg is moving with a velocity of 10 m/s. Its kinetic energy is:

   • A. 100 J
   • B. 150 J
   • C. 200 J
   • D. 300 J
   Answer and solution

   Answer: B

   Kinetic energy KE = ½mv² = ½ × 3 × 10² = ½ × 3 × 100 = 150 J.

2. Q2 · Laws of Motion (Class 11 — ~20% weight)

   A force of 20 N acts on a body of mass 5 kg for 4 seconds. The change in momentum of the body is:

   • A. 80 kg·m/s
   • B. 100 kg·m/s
   • C. 40 kg·m/s
   • D. 60 kg·m/s
   Answer and solution

   Answer: A

   Change in momentum Δp = Force × time = 20 × 4 = 80 kg·m/s (from impulse-momentum theorem).

3. Q3 · Rotational Dynamics (Class 12)

   A disc of radius 0.2 m and mass 2 kg is rotating about its central axis with angular velocity 10 rad/s. What is the angular momentum of the disc?

   • A. 0.2 kg m²/s
   • B. 0.4 kg m²/s
   • C. 0.8 kg m²/s
   • D. 1.0 kg m²/s
   Answer and solution

   Answer: B

   Moment of inertia I = (1/2)MR² = 0.5 × 2 × (0.2)² = 0.04 kg m². Angular momentum L = Iω = 0.04 × 10 = 0.4 kg m²/s.

4. Q4 · Magnetism and Matter (Class 12)

   A bar magnet of magnetic moment 5 A·m² is placed in a uniform magnetic field of 0.4 T making an angle of 30° with the field. The torque acting on the magnet is

   • A. 1.0 N·m
   • B. 2.0 N·m
   • C. 0.5 N·m
   • D. 1.5 N·m
   Answer and solution

   Answer: A

   Torque τ = MB sin θ = 5 × 0.4 × sin 30° = 5 × 0.4 × 0.5 = 1.0 N·m.

5. Q5 · Capacitance (Class 12)

   Three capacitors of capacitance 2 μF, 3 μF and 6 μF are connected in series to a 12 V battery. The charge on the 3 μF capacitor is

   • A. 36 μC
   • B. 12 μC
   • C. 18 μC
   • D. 24 μC
   Answer and solution

   Answer: B

   In series, charge is same on all. 1/Ceq = 1/2 + 1/3 + 1/6 = 1 μF⁻¹, so Ceq = 1 μF. Q = CeqV = 1 × 12 = 12 μC.

6. Q6 · Atoms and Nuclei (Class 12)

   In a hydrogen atom, an electron transitions from the fourth orbit to the second orbit. If the Rydberg constant is R = 1.097 × 10⁷ m⁻¹, the wavelength of the emitted photon (in nm) is approximately:

   • A. 397 nm
   • B. 486 nm
   • C. 656 nm
   • D. 720 nm
   Answer and solution

   Answer: B

   Using 1/λ = R(1/2² - 1/4²) = R(1/4 - 1/16) = R(3/16), we find λ ≈ 486 nm.

7. Q7 · Chemical Bonding and Molecular Structure (Class 11 — ~20% weight)

   According to VSEPR theory, which molecule has a square planar geometry?

   • A. SF₄
   • B. XeF₄
   • C. BF₃
   • D. NH₃
   Answer and solution

   Answer: B

   XeF₄ has 6 electron pairs (4 bonding, 2 lone pairs) around Xe, resulting in square planar geometry.

8. Q8 · Hydrocarbons (Class 11 — ~20% weight)

   Which of the following alkenes will show geometrical isomerism?

   • A. CH₂=CH₂
   • B. CH₃-CH=CH-CH₃
   • C. CH₂=CH-CH₃
   • D. CH₂=C(CH₃)₂
   Answer and solution

   Answer: B

   But-2-ene (CH₃-CH=CH-CH₃) has two different groups on each doubly bonded carbon atom, satisfying the requirement for geometrical (cis-trans) isomerism.

9. Q9 · d- and f-Block Elements (Class 12)

   Which of the following elements shows a maximum number of different oxidation states in its compounds?

   • A. Sc
   • B. Mn
   • C. Zn
   • D. Cu
   Answer and solution

   Answer: B

   Manganese (Mn) exhibits the maximum oxidation states from +2 to +7 due to the availability of both 3d and 4s electrons for bonding.

10. Q10 · Coordination Compounds (Class 12)

    Identify the type of isomerism exhibited by [Co(NH₃)₅Cl]SO₄ and [Co(NH₃)₅SO₄]Cl.

    • A. Geometrical isomerism
    • B. Optical isomerism
    • C. Ionization isomerism
    • D. Linkage isomerism
    Answer and solution

    Answer: C

    These complexes show ionization isomerism because they differ in the ions that are released when dissolved in water (Cl⁻ vs SO₄²⁻).