KCET · Previous year papers · 2021

KCET 2021 previous year paper practice · PYQ-pattern set

18 PYQ-pattern questions modelled on the 2021 paper (which had 240) · 320 min

Every question here is freshly worded in the pattern of the 2021 paper — same topics, style and difficulty — not the original questions, which Shishya does not reproduce.

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Solve these 18 2021-pattern questions as a timed mock — free

18 PYQ-pattern questions modelled on the 2021 paper (which had 240) · instant scoring · topic-wise analysis. Sign up with Google, free, to attempt and track your progress.

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KCET 2021 PYQ-pattern questions

Showing 10 of the 18 PYQ-pattern questions in this set — freshly worded in that year's pattern, not the original questions. Answers and solutions open under each question.

  1. Q1 · Laws of Motion (1st PUC)

    A block of mass 5 kg is placed on a rough horizontal surface with coefficient of friction 0.4. A horizontal force of 30 N is applied to the block. The acceleration of the block is: (g = 10 m/s²)

    • A. 2 m/s²
    • B. 4 m/s²
    • C. 6 m/s²
    • D. Zero
    Answer and solution

    Answer: A

    Friction force f = μmg = 0.4 × 5 × 10 = 20 N. Net force = 30 - 20 = 10 N. Acceleration a = F_net/m = 10/5 = 2 m/s².

  2. Q2 · Motion in a Straight Line (1st PUC)

    A particle starts from rest and moves with constant acceleration. The ratio of distances covered in successive equal time intervals of 2 seconds each is:

    • A. 1:2:3
    • B. 1:3:5
    • C. 1:4:9
    • D. 2:4:6
    Answer and solution

    Answer: B

    For motion with constant acceleration from rest, distances in successive equal time intervals are in the ratio 1:3:5:7... This follows from s_n = u + (a/2)(2n-1)t² with u=0.

  3. Q3 · Thermodynamics (1st PUC)

    One mole of an ideal gas at 400 K is heated at constant pressure until its volume doubles. If R = 8.3 J/(mol·K), the work done by the gas is:

    • A. 1660 J
    • B. 2490 J
    • C. 3320 J
    • D. 4150 J
    Answer and solution

    Answer: C

    At constant pressure, when volume doubles, temperature also doubles to 800 K. Work done W = nRΔT = 1 × 8.3 × (800-400) = 1 × 8.3 × 400 = 3320 J.

  4. Q4 · Electromagnetic Induction (2nd PUC)

    A rectangular coil of 200 turns and area 0.05 m² is rotated in a magnetic field of 0.3 T at 1200 rpm. The maximum emf induced in the coil is (take π = 3.14)

    • A. 377 V
    • B. 188.4 V
    • C. 628 V
    • D. 314 V
    Answer and solution

    Answer: A

    Maximum emf = NBAω, where ω = 2πf = 2 × 3.14 × (1200/60) = 125.6 rad/s. Thus emf = 200 × 0.3 × 0.05 × 125.6 = 377 V.

  5. Q5 · Current Electricity (2nd PUC)

    Two resistors of 8 Ω and 12 Ω are connected in parallel. Their equivalent resistance is

    • A. 4.8 Ω
    • B. 20 Ω
    • C. 10 Ω
    • D. 6 Ω
    Answer and solution

    Answer: A

    For parallel combination, 1/R = 1/8 + 1/12 = 5/24. Therefore R = 24/5 = 4.8 Ω.

  6. Q6 · Semiconductor Electronics (2nd PUC)

    In a p-n junction diode under forward bias, the width of the depletion layer:

    • A. Increases
    • B. Decreases
    • C. Remains constant
    • D. First increases then decreases
    Answer and solution

    Answer: B

    Under forward bias, the applied voltage opposes the built-in potential barrier, reducing the depletion layer width and allowing current to flow.

  7. Q7 · Some Basic Concepts of Chemistry (1st PUC)

    If 5×10²⁰ molecules are removed from 49 mg of H₂SO₄, how many moles of H₂SO₄ are left? (Take Avogadro's number Nₐ = 6×10²³ mol⁻¹, Molar mass of H₂SO₄ = 98 g/mol)

    • A. 4×10⁻⁴ mol
    • B. 5×10⁻⁴ mol
    • C. 4.17×10⁻⁴ mol
    • D. 3×10⁻⁴ mol
    Answer and solution

    Answer: C

    Initial moles = 49 mg /98 g/mol = 5×10⁻⁴ mol. Molecules removed correspond to 5×10²⁰/6×10²³ ≈ 0.83×10⁻⁴ mol (intended). Remaining = 5×10⁻⁴ − 0.83×10⁻⁴ = 4.17×10⁻⁴ mol.

  8. Q8 · Chemical Bonding and Molecular Structure (1st PUC)

    The shape of NH₃ molecule is:

    • A. Trigonal pyramidal
    • B. Tetrahedral
    • C. Trigonal planar
    • D. Linear
    Answer and solution

    Answer: A

    NH₃ has sp³ hybridization with one lone pair on nitrogen, resulting in a trigonal pyramidal shape.

  9. Q9 · Environmental Chemistry (1st PUC)

    Which of the following gases is primarily responsible for the greenhouse effect?

    • A. Oxygen
    • B. Nitrogen
    • C. Carbon dioxide
    • D. Argon
    Answer and solution

    Answer: C

    Carbon dioxide is the major greenhouse gas that traps heat in the atmosphere, contributing significantly to global warming.

  10. Q10 · p-Block Elements — Groups 13 and 14 (1st PUC)

    Which of the following is the most abundant element in the Earth's crust among Group 13 elements?

    • A. Boron
    • B. Aluminium
    • C. Gallium
    • D. Indium
    Answer and solution

    Answer: B

    Aluminium is the third most abundant element in Earth's crust and the most abundant metal.

Breakdown by subject

  • Physics

    6 questions

  • Chemistry

    8 questions

  • Mathematics

    4 questions

KCET 2021 previous year paper — frequently asked questions

Where can I solve the KCET 2021 previous year paper (PYQ) free online?
At https://shishya.in/exams/KA_KCET/pyq/2021 you can solve KCET 18 PYQ-pattern questions modelled on the 2021 paper free. Shishya does not reproduce the original paper: every question is freshly worded in that year's pattern — same topics, style and difficulty, new wording and numbers, and this set holds 18 questions, not the whole paper. They run as a timed mock with instant scoring, step-by-step solutions and topic-wise weak-area analysis. No fee and no coaching enrolment needed.
Are these the actual KCET 2021 paper questions?
No. They are PYQ-pattern questions modelled on the KCET 2021 paper — freshly worded practice questions in the same pattern, not the original questions, which Shishya does not reproduce. This set holds 18 questions.
Do these KCET 2021 pattern questions come with solutions and analysis?
Yes — every question carries a worked solution, and on submitting you get an instant score with a topic-wise breakdown showing exactly which areas to revise. Wrong answers are auto-collected into a free Mistake Notebook for one-tap re-practice until cleared.
Are previous year papers enough to crack KCET?
Previous-year papers are the best signal of what the exam actually tests, but they work best with targeted practice and a plan. On Shishya (all free): solve PYQ-pattern sets year-wise, drill weak topics via the Mistake Notebook, follow a day-by-day plan from the Personal Coach at https://shishya.in/coach and sit the Sunday All-India Live Test at https://shishya.in/live-test to see where you stand nationally.