Equation of state of a perfect gas, work done on compressing a gas; kinetic theory of gases — assumptions; concept of pressure; kinetic interpretation of temperature; rms speed; degrees of freedom; law of equipartition of energy; mean free path; Avogadro's number.
Study notes are still being prepared.
Don't wait — Shishya can teach you this topic right now, on demand.
Ask Shishya to teach this →Shishya is your personal tutor for this topic. Pick a starter or open a free chat.
Q1 · Kinetic Theory of Gases · EASY
A gas is enclosed in a container at 27°C. If the rms speed of the gas molecules is v, what will be the rms speed at 127°C?
Q2 · Kinetic Theory of Gases · MEDIUM
One mole of an ideal gas at temperature T occupies a volume V. The gas expands isothermally to volume 2V. What is the work done by the gas? (R is the universal gas constant)
Q3 · Kinetic Theory of Gases · MEDIUM
A gas molecule has 5 degrees of freedom. According to the law of equipartition of energy, what is the ratio of its molar specific heat at constant pressure to that at constant volume (γ = Cp/Cv)?
Q4 · Kinetic Theory of Gases · EASY
Two identical containers A and B contain the same ideal gas at the same temperature. The pressure in A is PA and in B is PB such that PA = 2PB. The ratio of the number of molecules in A to that in B is:
Q5 · Kinetic Theory of Gases · HARD
The mean free path of gas molecules depends on the diameter d of the molecules and the number density n as λ = 1/(√2 π d² n). If the pressure of a gas is doubled at constant temperature, the mean free path becomes: