5 real JEE Main questions on Solutions. Instant scoring and solutions, no signup — see where you stand in ~3 minutes.
Question 1 of 5
EASYA solution is prepared by dissolving 9.0 g of glucose (C₆H₁₂O₆, molar mass 180 g/mol) in 500 g of water. What is the molality of the solution (in mol/kg)?