IOQM · Previous year papers · 2024
IOQM 2024 previous year paper · official paper and PYQ-pattern practice
6 PYQ-pattern questions modelled on the 2024 paper (which had 30) · 180 min
Every question here is freshly worded in the pattern of the 2024 paper — same topics, style and difficulty — not the original questions, which Shishya does not reproduce.
The original 2024 paper, as HBCSE-TIFR (Mathematical Olympiad Cell) published it
- IOQM 2024 Question Paper - English ↗ · Question paper · English · PDF · 75 KB
- IOQM 2024 Question Paper - Hindi ↗ · Question paper · Hindi · PDF · 71 KB
- Answer key to IOQM 2024 ↗ · Answer key · English · PDF · 35 KB
Shishya's own practice questions, set out subject by subject like the real paper — not the original paper.
Solve these 6 2024-pattern questions as a timed mock — free
6 PYQ-pattern questions modelled on the 2024 paper (which had 30) · instant scoring · topic-wise analysis. Sign up with Google, free, to attempt and track your progress.
Stuck on a question from this set?
Ask Shishya — your free AI tutor — to explain any IOQM 2024-pattern question, concept, or shortcut, step by step, in your language.
Ask Shishya about this set →IOQM 2024 PYQ-pattern questions
Showing 6 of the 6 PYQ-pattern questions in this set — freshly worded in that year's pattern, not the original questions. Answers and solutions open under each question.
Q1 · Basic Preliminaries
What is 40% of 60% of 250?
- A. 50
- B. 60
- C. 75
- D. 90
Answer and solution
Answer: B
40% of 60% of 250 = (40/100) × (60/100) × 250 = 0.4 × 0.6 × 250 = 60.
Q2 · Combinatorics
In how many ways can 5 boys and 4 girls be arranged in a row such that no two girls sit together?
- A. 43200
- B. 86400
- C. 2880
- D. 1440
Answer and solution
Answer: A
Arrange 5 boys in 5! = 120 ways. This creates 6 gaps; place 4 girls in these gaps so no two are adjacent: 6P4 = 360. Total = 120 × 360 = 43200.
Q3 · Geometry
A circle with center O has radius 10 cm. Two chords AB and CD intersect at point P inside the circle such that AP = 8 cm, PB = 6 cm, and CP = 12 cm. Find the length of PD in cm.
- A. 3
- B. 4
- C. 5
- D. 6
Answer and solution
Answer: B
By the intersecting chords theorem, when two chords intersect inside a circle, AP × PB = CP × PD. Substituting: 8 × 6 = 12 × PD, so 48 = 12 × PD, giving PD = 4 cm.
Q4 · Trigonometry
If sin θ + cos θ = 7/5, where 0 < θ < π/2, find the value of 100 × sin θ × cos θ.
- A. 12
- B. 24
- C. 48
- D. 36
Answer and solution
Answer: C
Squaring both sides: sin²θ + cos²θ + 2sinθcosθ = 49/25. Since sin²θ + cos²θ = 1, we get 1 + 2sinθcosθ = 49/25, so 2sinθcosθ = 24/25, hence 100 × sinθcosθ = 12. [Correction 2026-08-31: answer key corrected to C after student report + independent re-verification. Squaring sin θ + cos θ = 7/5 gives 1 + 2sin θ cos θ = 49/25, so sin θ cos θ = 12/25. Therefore 100 × sin θ × cos θ = 100 × 12/25 = 48.]
Q5 · Number Theory
How many positive integers less than or equal to 120 are divisible by exactly one of 4 or 6 (but not both)?
- A. 30
- B. 32
- C. 34
- D. 36
Answer and solution
Answer: A
Multiples of 4 up to 120: 30; of 6: 20; of LCM 12: 10. Exactly one = (30+20) - 2*10 = 30.
Q6 · Algebra
Let x and y be real numbers satisfying x + y = 7 and x² + y² = 29. Find the value of x³ + y³.
- A. 91
- B. 133
- C. 147
- D. 161
Answer and solution
Answer: B
Using the identity x³ + y³ = (x + y)³ - 3xy(x + y), first find xy from (x + y)² = x² + y² + 2xy, so 49 = 29 + 2xy giving xy = 10. Then x³ + y³ = 7³ - 3(10)(7) = 343 - 210 = 133.
Breakdown by subject
Mathematics
6 questions