UTET · Mathematics (Paper I — Classes I-V)

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Mathematical Content

Mathematics content for Class I-V.

In the official syllabus: UBSE — Structure and Content of Syllabus - UTET I (classes I to V) and UTET II (classes VI to VIII), listed by the…, UTET I, IV Mathematics, a. Content (pages 2-3) (a scanned PDF, read by AI twice; read 29 Sept 2026). The pages print no date; UBSE's site lists them for UTET.

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Mathematical Content for Classes I-V

Overview

Mathematical Content forms the foundation of Paper I Mathematics in UTET, testing your grasp of concepts taught to primary school children (Classes I-V).

The content spans seven interconnected areas: numbers and place value, four basic operations, fractions and decimals, measurement, geometry, data handling, and patterns. Questions test both your conceptual understanding and your ability to solve problems at the primary level. Expect straightforward computation problems alongside word problems requiring logical interpretation.

Mastery here requires thinking like a primary teacher—understanding not just how to solve problems, but why methods work and where children commonly struggle. The syllabus aligns closely with NCERT textbooks for Classes I-V, so familiarity with those examples is valuable.


Key Concepts

  • Place value system is the backbone of number sense. Each digit's value depends on its position—the same digit 5 means 5, 50, or 500 depending on placement. Indian place value follows the pattern: ones, tens, hundreds, thousands, ten-thousands, lakhs.
  • Zero as a placeholder is critical. In 502, zero holds the tens place; without understanding this, children confuse 502 with 52.
  • Fractions represent parts of a whole. The denominator tells how many equal parts the whole is divided into; the numerator tells how many parts we have. Equivalent fractions (1/2 = 2/4 = 3/6) represent the same quantity.
  • Decimals extend place value to the right of the decimal point. The first place after the decimal is tenths (1/10), the second is hundredths (1/100).
  • Measurement requires standard units because non-standard units (handspan, footstep) vary from person to person. Metric relationships: 1 km = 1000 m, 1 kg = 1000 g, 1 litre = 1000 ml.
  • Geometry at primary level is intuitive. Children learn shapes through observation and handling objects before formal definitions. A square is a special rectangle with all sides equal.
  • Data handling develops interpretation skills. Pictographs use symbols to represent quantities; bar graphs use rectangular bars whose lengths represent values.
  • Patterns build algebraic thinking. Recognising what comes next in a sequence develops logical reasoning and prepares children for algebra.

Formulas / Key Facts

Numbers and Place Value

  • Indian system: Ones → Tens → Hundreds → Thousands → Ten Thousands → Lakhs
  • Largest 5-digit number: 99,999; Smallest 5-digit number: 10,000
  • Roman numerals: I=1, V=5, X=10, L=50, C=100, D=500, M=1000
  • Rule: Smaller numeral before larger means subtraction (IV=4, IX=9)

Operations

  • Dividend = Divisor × Quotient + Remainder
  • Order of operations: Brackets → Division → Multiplication → Addition → Subtraction

Fractions and Decimals

  • To find equivalent fractions: multiply or divide both numerator and denominator by the same number
  • To add/subtract fractions: first make denominators same (LCM)
  • Decimal to fraction: 0.25 = 25/100 = 1/4

Measurement

  • Length: 1 km = 1000 m; 1 m = 100 cm; 1 cm = 10 mm
  • Weight: 1 kg = 1000 g
  • Capacity: 1 litre = 1000 ml
  • Time: 1 hour = 60 minutes; 1 minute = 60 seconds; 1 day = 24 hours

Geometry

  • Perimeter of rectangle = 2 × (length + breadth)
  • Perimeter of square = 4 × side
  • Area of rectangle = length × breadth
  • Area of square = side × side

Data Handling

  • In pictographs, always note the key (what one symbol represents)
  • Bar heights/lengths directly show quantities for comparison

Worked Examples

Example 1: Place Value Write the number name and expanded form of 74,682.

Solution:

  • Number name: Seventy-four thousand six hundred eighty-two
  • Expanded form: 70,000 + 4,000 + 600 + 80 + 2
  • Place values: 7 is in ten-thousands place (value 70,000), 4 in thousands (4,000), 6 in hundreds (600), 8 in tens (80), 2 in ones (2)

Example 2: Fractions Add 2/5 and 1/3.

Solution:

  • Find LCM of denominators 5 and 3: LCM = 15
  • Convert: 2/5 = 6/15 and 1/3 = 5/15
  • Add: 6/15 + 5/15 = 11/15
  • Answer: 11/15

Example 3: Measurement Word Problem A rope is 8 m 45 cm long. If 3 m 70 cm is cut off, what length remains?

Solution:

  • Convert to cm: 8 m 45 cm = 845 cm; 3 m 70 cm = 370 cm
  • Subtract: 845 – 370 = 475 cm
  • Convert back: 475 cm = 4 m 75 cm
  • Answer: 4 m 75 cm

Example 4: Area and Perimeter A rectangular garden is 25 m long and 18 m wide. Find its perimeter and area.

Solution:

  • Perimeter = 2 × (25 + 18) = 2 × 43 = 86 m
  • Area = 25 × 18 = 450 m²
  • Answer: Perimeter = 86 m, Area = 450 square metres

Common Mistakes

  • Confusing place value with face value → Face value of 7 in 4,782 is always 7; place value is 700. Questions often test this distinction.
  • Subtracting fractions without common denominators → Students write 3/4 – 1/2 = 2/2 = 1 (wrong). Correct: Convert to 3/4 – 2/4 = 1/4.
  • Mixing up perimeter and area → Perimeter is the boundary length (linear units like m); area is the surface covered (square units like m²). Read questions carefully.
  • Forgetting to carry or borrow in operations → In 456 + 278, the ones column gives 14, so write 4 and carry 1 to tens. Skipping the carry gives wrong answers.
  • Misreading Roman numerals → IX means 10–1=9, not 11. Remember: smaller before larger = subtract; smaller after larger = add.
  • Ignoring units in measurement → Adding 3 km + 500 m directly as 3500 is wrong. Convert first: 3 km = 3000 m, then 3000 + 500 = 3500 m = 3 km 500 m.

Quick Reference

  • Place value pattern: …Lakhs, Ten-thousands, Thousands, Hundreds, Tens, Ones
  • Fraction addition rule: Same denominator first, then add numerators
  • Metric conversions: Kilo = 1000, Centi = 1/100, Milli = 1/1000
  • Perimeter = boundary length; Area = surface covered
  • Roman subtraction pairs: IV=4, IX=9, XL=40, XC=90, CD=400, CM=900
  • Dividend = Divisor × Quotient + Remainder (verify division)

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A fruit seller has 3,456 oranges. He arranges them equally in 12 baskets. How many oranges are there in each basket?

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2 practice questions on Mathematical Content for UTET, with answers

Shishya's practice questions, written with AI. Each answer was checked by an automated second pass, not by a person.

  1. 1.A farmer harvested 2,850 kg of wheat. He sold 3/5 of it to a trader and gave 1/10 of the total to his workers. How many kilograms of wheat does he have left?

    • (A)855 kg
    • (B)570 kg
    • (C)1,140 kg
    • (D)285 kg
    Show the answer and solution

    Answer: (A) 855 kg

    Solution: Step 1: Find wheat sold to trader: 3/5 of 2,850 = (3 × 2,850) ÷ 5 = 8,550 ÷ 5 = 1,710 kg. Step 2: Find wheat given to workers: 1/10 of 2,850 = 2,850 ÷ 10 = 285 kg. Step 3: Find total wheat given away: 1,710 + 285 = 1,995 kg. Step 4: Find wheat left: 2,850 - 1,995 = 855 kg. Therefore, the farmer has 855 kg of wheat left.

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  2. 2.A shopkeeper has 4,725 pencils. He packs them equally into 15 boxes. He then sells 9 boxes. How many pencils does he have left?

    • (A)1,890
    • (B)2,835
    • (C)1,575
    • (D)2,520
    Show the answer and solution

    Answer: (A) 1,890

    Solution: Step 1: Find pencils in each box by dividing total pencils by number of boxes: 4,725 ÷ 15 = 315 pencils per box. Step 2: Find pencils sold by multiplying pencils per box by boxes sold: 315 × 9 = 2,835 pencils sold. Step 3: Find pencils left by subtracting sold pencils from total: 4,725 - 2,835 = 1,890 pencils. Therefore, the shopkeeper has 1,890 pencils left.

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Notes generated on 28 Jun 2026