SBI Clerk · Numerical Ability

Mensuration

2D and basic 3D mensuration.

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Mensuration

Overview

Mensuration deals with the measurement of geometric shapes — calculating perimeter, area, surface area, and volume. The questions typically involve basic 2D shapes (rectangles, circles, triangles) and simple 3D solids (cubes, cylinders, cuboids).

Mastery of mensuration requires memorizing key formulas and applying them quickly. Unlike other arithmetic topics, there's little room for shortcuts — you either know the formula or you don't. The good news: the formulas are finite and the application is straightforward. Focus on speed and accuracy rather than complex problem-solving strategies.

Most questions test direct formula application with one or two calculation steps. Occasionally, you'll encounter problems combining two shapes (like a square inscribed in a circle) or requiring you to find dimensions before calculating area/volume.

Key Concepts

  • Perimeter is the total boundary length of a 2D shape; Area is the space enclosed within that boundary.
  • Surface Area of a 3D solid is the total area of all its faces; Volume is the space it occupies.
  • For 3D solids, distinguish between Curved Surface Area (CSA) — only the curved portion — and Total Surface Area (TSA) — curved plus flat faces.
  • When a shape is inscribed in another (e.g., circle in square), their dimensions share a relationship — identify the connecting element (diagonal, diameter, side).
  • Units matter: Area uses square units (cm², m²), Volume uses cubic units (cm³, m³). Converting between units requires squaring or cubing the conversion factor.
  • A hemisphere is half a sphere — its CSA excludes the flat circular base, while TSA includes it.
  • For composite shapes, break them into standard shapes, calculate separately, then add or subtract as needed.

Formulas / Key Facts

2D Shapes

ShapePerimeterArea
Square (side a)4aa²
Rectangle (l × b)2(l + b)l × b
Circle (radius r)2πrπr²
Triangle (sides a, b, c)a + b + c½ × base × height
Equilateral Triangle (side a)3a(√3/4) × a²
Right Triangle (legs a, b)a + b + √(a² + b²)½ × a × b
Parallelogram (base b, height h)2(a + b)b × h
Trapezium (parallel sides a, b; height h)a + b + c + d½ × (a + b) × h

Key relationships:

  • Diagonal of square = a√2
  • Diagonal of rectangle = √(l² + b²)
  • Circumference = π × diameter

3D Shapes

SolidCurved Surface AreaTotal Surface AreaVolume
Cube (side a)4a²6a²a³
Cuboid (l × b × h)2h(l + b)2(lb + bh + hl)l × b × h
Cylinder (radius r, height h)2πrh2πr(r + h)πr²h
Cone (radius r, height h, slant l)πrlπr(r + l)⅓πr²h
Sphere (radius r)4πr²4πr²(4/3)πr³
Hemisphere (radius r)2πr²3πr²(2/3)πr³

Slant height of cone: l = √(r² + h²)

Diagonal of cuboid: √(l² + b² + h²)

Worked Examples

Example 1: Finding Area from Perimeter

The perimeter of a rectangular field is 80 m. If the length is 10 m more than the breadth, find the area.

Solution:

  • Let breadth = b, then length = b + 10
  • Perimeter: 2(l + b) = 80 → l + b = 40
  • Substituting: (b + 10) + b = 40 → 2b = 30 → b = 15 m
  • Length = 25 m
  • Area = 25 × 15 = 375 m²

Example 2: Volume of a Cylinder

A cylindrical tank has diameter 14 m and height 5 m. Find its volume. (Use π = 22/7)

Solution:

  • Diameter = 14 m → Radius = 7 m
  • Volume = πr²h = (22/7) × 7 × 7 × 5
  • Volume = 22 × 7 × 5 = 770 m³

Example 3: Composite Shape

A square of side 14 cm has a circle of maximum possible size cut from it. Find the area of the remaining portion. (π = 22/7)

Solution:

  • Maximum circle that fits → diameter = side of square = 14 cm
  • Radius = 7 cm
  • Area of square = 14² = 196 cm²
  • Area of circle = (22/7) × 7² = 154 cm²
  • Remaining area = 196 − 154 = 42 cm²

Common Mistakes

  • Confusing radius and diameter → Always check what's given. Diameter = 2 × radius. Half the radius when diameter is provided before applying formulas.
  • Mixing up CSA and TSA → Read carefully whether the question asks for "curved surface" or "total surface." A closed cylinder's TSA includes two circular ends; CSA does not.
  • Forgetting to square/cube when converting units → 1 m² = 10,000 cm² (not 100). 1 m³ = 1,000,000 cm³. Always square for area, cube for volume.
  • Using wrong triangle area formula → For any triangle, area = ½ × base × height, where height is perpendicular to that base. For equilateral triangles only, use (√3/4)a².
  • Miscalculating slant height vs vertical height in cones → Slant height (l) is the side length; vertical height (h) goes straight down. Related by l² = r² + h².

Quick Reference

  • Square: Area = side², Diagonal = side × √2
  • Circle: Area = πr², Circumference = 2πr
  • Cylinder volume = πr²h; Cube volume = a³
  • Sphere volume = (4/3)πr³; Hemisphere volume = (2/3)πr³
  • TSA of cylinder = 2πr(r + h); CSA of cylinder = 2πrh
  • Use π = 22/7 when radius/diameter is multiple of 7; else use 3.14

Drafted with AI from Shishya's syllabus outline for this exam · Reviewed by a person: not yet · Report an error

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The length of a rectangle is 24 cm and its breadth is 18 cm. If the length is increased by 25% and the breadth is decreased by 20%, what will be the percentage change in the area of the rectangle?

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3 practice questions on Mensuration for SBI Clerk, with answers

Shishya's practice questions, written with AI. Each answer was checked by an automated second pass, not by a person.

  1. 1.The radius of a circular garden is 14 m. What is the cost of fencing it at the rate of Rs. 25 per meter?

    • (A)Rs. 2100
    • (B)Rs. 2200
    • (C)Rs. 2400
    • (D)Rs. 2800
    Show the answer and solution

    Answer: (B) Rs. 2200

    Solution: Circumference = 2πr = 2 × (22/7) × 14 = 88 m. Cost = 88 × 25 = Rs. 2200.

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  2. 2.The length of a rectangular field is twice its breadth. If the perimeter of the field is 96 meters, what is the area of the field in square meters?

    • (A)480
    • (B)512
    • (C)576
    • (D)640
    Show the answer and solution

    Answer: (B) 512

    Solution: Let breadth = b, length = 2b. Perimeter = 2(2b + b) = 6b = 96, so b = 16m. Length = 32m. Area = 16 × 32 = 512 sq.m.

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  3. 3.A rectangular water tank is 8 metres long, 6 metres wide and 3 metres high. If water is filled to 75% of its height, how many litres of water does the tank contain? (1 cubic metre = 1000 litres)

    • (A)108000 litres
    • (B)120000 litres
    • (C)144000 litres
    • (D)96000 litres
    Show the answer and solution

    Answer: (A) 108000 litres

    Solution: Step 1: Calculate total volume of tank. Volume = length × width × height = 8 × 6 × 3 = 144 cubic metres. Step 2: Calculate volume of water filled. Water is filled to 75% of height, so filled volume = 144 × (75/100) = 144 × 0.75 = 108 cubic metres. Step 3: Convert to litres. 1 cubic metre = 1000 litres, so 108 cubic metres = 108 × 1000 = 108000 litres. Therefore, the tank contains 108000 litres of water.

    Report an error

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Notes generated on 11 Sept 2026