NEET UG 2025 previous year paper practice · PYQ-pattern set

NEET UG 2025 PYQ-pattern questions

Showing 10 of the 20 PYQ-pattern questions in this set — freshly worded in that year's pattern, not the original questions. Answers and solutions open under each question.

1. Q1 · Kinematics

   A particle moves along a straight line such that its displacement x at time t is given by x = 2t³ - 9t² + 12t + 4 (where x is in meters and t is in seconds). At what time does the particle come to rest momentarily?

   • A. 1 s and 2 s
   • B. 2 s and 3 s
   • C. 1 s and 3 s
   • D. Only at 2 s
   Answer and solution

   Answer: A

   Velocity v = dx/dt = 6t² - 18t + 12. At rest, v = 0, so 6t² - 18t + 12 = 0, giving t² - 3t + 2 = 0, which factors to (t-1)(t-2) = 0, thus t = 1 s and 2 s.

2. Q2 · Laws of Motion

   A block of mass 4 kg rests on a horizontal surface. The coefficient of static friction between the block and surface is 0.6. What is the minimum horizontal force required to just move the block? (Take g = 10 m/s²)

   • A. 12 N
   • B. 18 N
   • C. 24 N
   • D. 40 N
   Answer and solution

   Answer: C

   Minimum force to just move equals maximum static friction: F = μₛN = μₛmg = 0.6 × 4 × 10 = 24 N.

3. Q3 · Motion of System of Particles and Rigid Body

   A uniform rod of length L and mass M is pivoted at one end and released from horizontal position. What is the angular acceleration of the rod at the instant of release?

   • A. g/L
   • B. 2g/L
   • C. 3g/2L
   • D. g/2L
   Answer and solution

   Answer: C

   Torque τ = Mg(L/2), moment of inertia I = ML²/3. Angular acceleration α = τ/I = Mg(L/2)/(ML²/3) = 3g/2L.

4. Q4 · Waves

   Two sound waves of frequencies 256 Hz and 260 Hz are sounded together. The number of beats heard per second is:

   • A. 2
   • B. 4
   • C. 8
   • D. 516
   Answer and solution

   Answer: B

   Number of beats per second = |f₁ - f₂| = |256 - 260| = 4 beats/second.

5. Q5 · Electromagnetic Waves

   Which of the following electromagnetic waves has the shortest wavelength?

   • A. X-rays
   • B. Ultraviolet rays
   • C. Infrared rays
   • D. Microwaves
   Answer and solution

   Answer: A

   In the electromagnetic spectrum, X-rays have wavelength range 10⁻⁸ to 10⁻¹² m, which is shorter than UV (10⁻⁸ to 10⁻⁷ m), IR (10⁻³ to 10⁻⁶ m), and microwaves (10⁻¹ to 10⁻³ m).

6. Q6 · Physical World and Measurement

   The dimensions of physical quantity X in the equation Force = X × velocity² are:

   • A. ML⁻¹
   • B. ML⁻³T²
   • C. MLT⁻²
   • D. ML²T⁻¹
   Answer and solution

   Answer: A

   From Force = X × velocity², we get X = Force/velocity² = [MLT⁻²]/[LT⁻¹]² = [MLT⁻²]/[L²T⁻²] = [ML⁻¹].

7. Q7 · Gravitation

   The ratio of escape velocities from Earth and a planet having twice the radius and same mean density as Earth is:

   • A. 1:1
   • B. 1:2
   • C. 2:1
   • D. 1:√2
   Answer and solution

   Answer: B

   Escape velocity v = √(2gR) = √(2GM/R) = √(2G(4/3)πR³ρ/R) = R√(8πGρ/3). Since density is same, v ∝ R. Therefore, vₑ/vₚ = Rₑ/Rₚ = Rₑ/(2Rₑ) = 1:2.

8. Q8 · Properties of Bulk Matter

   A cube of side 10 cm and density 800 kg/m³ floats in water. The volume of the cube immersed in water is (density of water = 1000 kg/m³):

   • A. 500 cm³
   • B. 600 cm³
   • C. 700 cm³
   • D. 800 cm³
   Answer and solution

   Answer: D

   For floating equilibrium, weight = buoyant force. Volume of cube = 10³ = 1000 cm³. (800)(1000×10⁻⁶)(g) = (1000)(V_immersed)(g), so V_immersed = 0.8 × 1000 cm³ = 800 cm³.

9. Q9 · Behaviour of Perfect Gases and Kinetic Theory

   An ideal gas is enclosed in a container at 27°C. If the rms speed of the gas molecules is 500 m/s, what will be the rms speed at 127°C?

   • A. 577 m/s
   • B. 625 m/s
   • C. 707 m/s
   • D. 750 m/s
   Answer and solution

   Answer: A

   rms speed is proportional to √T. v₂/v₁ = √(T₂/T₁) = √(400/300) = √(4/3) = 1.1547. v₂ = 500 × 1.1547 ≈ 577 m/s.

10. Q10 · Magnetic Effects of Current and Magnetism

    A charged particle of mass m and charge q enters a uniform magnetic field B with velocity v perpendicular to the field. If the radius of the circular path is r, what will be the new radius if the velocity is doubled and the magnetic field is halved?

    • A. r
    • B. 2r
    • C. 4r
    • D. 8r
    Answer and solution

    Answer: C

    Radius r = mv/(qB). When v becomes 2v and B becomes B/2, new radius = m(2v)/(q×B/2) = 4mv/(qB) = 4r.