MPESB Group · Reasoning and Aptitude

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Direction Sense

Direction-based path problems.

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Direction Sense

Overview

Direction Sense is a fundamental topic in the Reasoning and Aptitude section of MPESB Group 1/2/3 exams. These problems test your ability to track movement, orientation, and spatial relationships when a person or object moves through a series of direction changes.

Students who can quickly visualize paths and calculate final positions gain a significant time advantage. The key skills tested are: understanding cardinal directions, tracking turns (left/right), and calculating straight-line distances using basic geometry.

Direction Sense problems appear in two main forms: finding the final direction someone faces, and finding the shortest distance between start and end points. Both require systematic tracking rather than guesswork.

Key Concepts

  • Cardinal Directions: The four main directions are North (N), South (S), East (E), and West (W). North is always shown at the top in standard diagrams.
  • Intermediate Directions: North-East (NE), North-West (NW), South-East (SE), and South-West (SW) lie exactly between cardinal directions at 45° angles.
  • Clockwise Order: Moving clockwise from North: N → NE → E → SE → S → SW → W → NW → N. This cycle helps determine results of turns.
  • Left Turn Rule: A left turn means rotating 90° counter-clockwise. From North, a left turn faces West. From East, a left turn faces North.
  • Right Turn Rule: A right turn means rotating 90° clockwise. From North, a right turn faces East. From South, a right turn faces West.
  • Opposite Directions: N↔S and E↔W are opposite pairs. NE↔SW and NW↔SE are opposite intermediate pairs.
  • Shortest Distance: The straight-line distance between two points, calculated using the Pythagorean theorem when the path forms a right angle.
  • Shadow and Sun Direction: At sunrise, shadows fall West (sun in East). At sunset, shadows fall East (sun in West). At noon, shadows are shortest and fall North in India (Northern Hemisphere).

Formulas / Key Facts

Shortest Distance Formula: When final displacement forms a right-angled path with legs a and b: Shortest Distance = √(a² + b²)

Turn Calculations:

  • 90° right from N = E
  • 90° left from N = W
  • 180° turn (about turn) = opposite direction
  • Two consecutive left turns = 180° turn
  • Two consecutive right turns = 180° turn
  • Four right turns (or four left turns) = original direction

Angle Between Directions:

  • Adjacent cardinal directions: 90° apart
  • Cardinal to adjacent intermediate: 45° apart
  • Opposite directions: 180° apart

Shadow Rules for Indian Region:

  • Morning (sunrise ~6 AM): Sun in East, shadow towards West
  • Evening (sunset ~6 PM): Sun in West, shadow towards East
  • Noon: Shadow towards North (shortest length)

Distance Conversion:

  • When movements are along perpendicular axes, net displacement = algebraic sum along each axis
  • North-South movements: North is positive, South is negative
  • East-West movements: East is positive, West is negative

Worked Examples

Example 1: Finding Final Direction

Problem: Ramesh starts facing North. He turns right, then turns right again, then turns left. Which direction is he facing now?

Solution:

  • Start: Facing North
  • Turn right (90° clockwise): Now facing East
  • Turn right again: Now facing South
  • Turn left (90° counter-clockwise): Now facing East

Answer: East


Example 2: Finding Shortest Distance

Problem: A man walks 4 km North, then 3 km East. What is the shortest distance from his starting point?

Solution:

  • Movement forms a right-angled triangle
  • Vertical leg (North) = 4 km
  • Horizontal leg (East) = 3 km
  • Shortest distance = √(4² + 3²) = √(16 + 9) = √25 = 5 km

Answer: 5 km


Example 3: Complex Path Problem

Problem: Meena walks 6 km South, then 8 km West, then 6 km North. How far and in which direction is she from the starting point?

Solution:

  • Draw the path step by step
  • 6 km South, then 8 km West, then 6 km North
  • Net North-South: 6 km South − 6 km North = 0 (back to original latitude)
  • Net East-West: 8 km West
  • Final position: 8 km directly West of starting point

Answer: 8 km West


Example 4: Shadow-Based Problem

Problem: One morning, Suresh was walking. His shadow fell to his right. Which direction was he facing?

Solution:

  • Morning = Sun in East
  • Shadow falls opposite to sun = Shadow towards West
  • If shadow is to his right, West is on his right
  • When West is on right, you are facing South

Answer: South

Common Mistakes

  • Confusing left/right with map directions → Fix: Left/right are relative to the person's current facing direction, not the map. Always track which way the person faces before applying the turn.
  • Forgetting to track intermediate positions → Fix: Draw a rough diagram for every problem. Mark each movement with arrows and distances. Never try to solve complex paths mentally.
  • Adding distances instead of finding displacement → Fix: Total distance walked ≠ shortest distance from start. The question asks for straight-line distance, which requires considering direction, not just adding all segments.
  • Reversing shadow logic → Fix: Remember "shadow falls away from sun." Morning sun in East means shadow in West. If someone's shadow is behind them, they face the sun.
  • Misapplying Pythagoras for non-perpendicular paths → Fix: The √(a² + b²) formula works only when the final displacement legs are at 90°. For other angles, you need different approaches or the path must be simplified first.

Quick Reference

  • Clockwise from North: N → E → S → W → N (each step is a right turn)
  • Right turn = 90° clockwise; Left turn = 90° counter-clockwise
  • Shortest distance uses Pythagoras: √(a² + b²) for perpendicular displacements
  • Morning shadow falls West; Evening shadow falls East
  • Always draw diagrams — place North at top, mark each move with arrows
  • Net displacement = combine all North-South movements, then all East-West movements separately

Drafted with AI from Shishya's syllabus outline for this exam · Reviewed by a person: not yet · Report an error

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A person walks 5 km towards North, then turns right and walks 3 km, then turns right again and walks 5 km. In which direction is he from his starting point?

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  • Q1 · Direction Sense · EASY

    A person walks 5 km towards North, then turns right and walks 3 km, then turns right again and walks 5 km. In which direction is he from his starting point?

  • Q2 · Direction Sense · EASY

    Ramesh starts from his house and walks 10 km towards East. He then turns left and walks 6 km, then turns left again and walks 10 km. How far is he from his starting point?

  • Q3 · Direction Sense · MEDIUM

    A man is facing North. He turns 45 degrees clockwise, then 180 degrees anticlockwise, and then 270 degrees clockwise. Which direction is he facing now?

  • Q4 · Direction Sense · HARD

    A cyclist starts from point A and rides 15 km towards North to reach point B. From B, he turns 135 degrees clockwise and rides 10 km to reach point C. What is the straight-line distance between point A and point C? (Use: square root of 2 = 1.41)

  • Q5 · Direction Sense · MEDIUM

    Ramesh walks 5 km towards North from his house. He then turns right and walks 3 km. After that, he turns right again and walks 8 km. Finally, he turns left and walks 2 km to reach his office. What is the shortest straight-line distance between his house and office?

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Notes generated on 13 Sept 2026