IBPS Clerk · Numerical Ability

Quadratic Equations

Compare two quadratic equations and decide x-y relation.

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Quadratic Equations

Overview

Quadratic equations in IBPS Clerk Prelims follow a fixed, predictable pattern: you receive two equations (one in x, one in y), solve both, then compare the roots to determine the relationship between x and y.

Unlike school-level quadratic problems, the exam doesn't ask you to find roots for their own sake. Your job is to compare values: Is x greater than y? Are they equal? Is the relationship indeterminate? The equations are designed to have integer roots (usually between -10 and +10), so factorization works smoothly without needing the quadratic formula.

Students who drill this topic properly can finish all 5 questions in under 3 minutes—a significant advantage when time pressure is intense in the 60-question, 60-minute Prelims paper.


Key Concepts

  • Standard form: A quadratic equation is written as ax² + bx + c = 0, where a, b, c are constants and a ≠ 0.
  • Roots: The values of x (or y) that satisfy the equation. Each quadratic has exactly two roots (which may be equal or distinct).
  • Sum of roots = -b/a; Product of roots = c/a. Use these to verify your factorization quickly.
  • Factorization method: Split the middle term into two parts whose product equals a × c and whose sum equals b.
  • Sign convention for comparison: After finding both roots of each equation, compare all possible pairs and decide the universal relationship.
  • Answer options in IBPS exams typically are:
    • x > y (all values of x are greater than all values of y)
    • x < y
    • x ≥ y (x is greater than or equal to y in all cases)
    • x ≤ y
    • x = y or relationship cannot be established
  • "Cannot be established": If some pairs give x > y and others give x < y, the relationship is indeterminate.

Formulas / Key Facts

Formula / FactContext
ax² + bx + c = 0Standard quadratic form
Sum of roots = -b/aQuick verification after factorization
Product of roots = c/aHelps confirm root signs (+/−)
Discriminant = b² - 4acIf negative, no real roots (rare in Clerk exams)
(x - p)(x - q) = 0 means roots are p and qFactorization outcome
For comparison: arrange roots on a number lineVisual clarity for relationship

IBPS-specific fact: Equations are crafted so roots are small integers. If you're getting messy decimals, recheck your factorization.


Worked Examples

Example 1

Equation I: x² - 7x + 12 = 0 Equation II: y² - 9y + 20 = 0

Step 1: Solve for x Find two numbers that multiply to 12 and add to 7: 3 and 4 x² - 3x - 4x + 12 = 0 x(x - 3) - 4(x - 3) = 0 (x - 3)(x - 4) = 0 x = 3 or x = 4

Step 2: Solve for y Find two numbers that multiply to 20 and add to 9: 4 and 5 y² - 4y - 5y + 20 = 0 y(y - 4) - 5(y - 4) = 0 (y - 4)(y - 5) = 0 y = 4 or y = 5

Step 3: Compare x values: 3, 4 y values: 4, 5

ComparisonResult
3 vs 4x < y
3 vs 5x < y
4 vs 4x = y
4 vs 5x < y

Answer: x ≤ y


Example 2

Equation I: x² + 5x + 6 = 0 Equation II: y² + 7y + 10 = 0

Step 1: Solve for x Factors of 6 that add to 5: 2 and 3 (x + 2)(x + 3) = 0 x = -2 or x = -3

Step 2: Solve for y Factors of 10 that add to 7: 2 and 5 (y + 2)(y + 5) = 0 y = -2 or y = -5

Step 3: Compare x values: -2, -3 y values: -2, -5

ComparisonResult
-2 vs -2x = y
-2 vs -5x > y (since -2 > -5)
-3 vs -2x < y
-3 vs -5x > y

Some pairs give x > y, others give x < y. Answer: Relationship cannot be established


Example 3

Equation I: 2x² - 7x + 3 = 0 Equation II: 2y² - 7y - 4 = 0

Step 1: Solve for x a × c = 2 × 3 = 6 Find two numbers that multiply to 6 and add to -7: -6 and -1 2x² - 6x - x + 3 = 0 2x(x - 3) - 1(x - 3) = 0 (2x - 1)(x - 3) = 0 x = 0.5 or x = 3

Step 2: Solve for y a × c = 2 × (-4) = -8 Find two numbers that multiply to -8 and add to -7: -8 and +1 2y² - 8y + y - 4 = 0 2y(y - 4) + 1(y - 4) = 0 (2y + 1)(y - 4) = 0 y = -0.5 or y = 4

Step 3: Compare x values: 0.5, 3 y values: -0.5, 4

ComparisonResult
0.5 vs -0.5x > y
0.5 vs 4x < y
3 vs -0.5x > y
3 vs 4x < y

Mixed results. Answer: Relationship cannot be established


Common Mistakes

  • Ignoring negative roots in comparison: Students forget that -3 > -5. Fix: Draw a number line mentally; numbers increase as you move right.
  • Assuming single overlap means x = y: If x = 4 and y = 4 appear, but other values differ, the answer is ≥ or ≤, not strictly equal. Fix: Compare ALL root pairs.
  • Sign errors during factorization: When c is positive and b is negative, both factors are negative. When c is negative, factors have opposite signs. Fix: Check product and sum before finalizing.
  • Rushing to "cannot be established": Some students pick this option too quickly. Fix: Systematically compare all four pairs (2 x-values × 2 y-values).
  • Forgetting to divide when a ≠ 1: For 2x² equations, after factorizing to (2x - 1) = 0, the root is x = 1/2, not x = 1. Fix: Always solve the bracket completely.

Quick Reference

  • Factorize both equations → Get two roots each → Compare all four pairs
  • Sum of roots = -b/a, Product of roots = c/a (use to verify)
  • All x > all y → Answer: x > y
  • All x < all y → Answer: x < y
  • Some equal, rest one-sided → Answer: x ≥ y or x ≤ y
  • Mixed results → Answer: Cannot be established
  • Typical root range in IBPS Clerk: integers from -10 to +10

Drafted with AI from Shishya's syllabus outline for this exam · Reviewed by a person: not yet · Report an error

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I. x² - 11x + 28 = 0 II. y² - 15y + 56 = 0 What is the relation between x and y?

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  • Q1 · Quadratic Equations · EASY

    I. x² - 11x + 28 = 0 II. y² - 15y + 56 = 0 What is the relation between x and y?

  • Q2 · Quadratic Equations · MEDIUM

    I. 2x² - 13x + 21 = 0 II. 2y² - 19y + 44 = 0 What is the relation between x and y?

  • Q3 · Quadratic Equations · EASY

    I. x² - 9x + 20 = 0 II. y² - 13y + 42 = 0 What is the relation between x and y?

  • Q4 · Quadratic Equations · MEDIUM

    I. 3x² + 16x + 21 = 0 II. 6y² + 17y + 12 = 0 What is the relation between x and y?

  • Q5 · Quadratic Equations · MEDIUM

    I. x² - 8x + 15 = 0 II. y² - 7y + 12 = 0 What is the relation between x and y?

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Notes generated on 11 Sept 2026