HSSC CET · Quantitative Ability

More Haryana government exams →

Simple and Compound Interest

SI and CI calculations and applications.

Share with your prep group:WhatsApp

Test yourself on Simple and Compound Interest

5 practice questions for HSSC CET with instant answers — no signup, ~3 minutes.

Take the 5-question quiz →

Simple and Compound Interest

Overview

Simple and Compound Interest is a high-scoring topic in HSSC CET Quantitative Ability. Questions typically involve straightforward formula application, but examiners test your understanding through word problems involving loans, deposits, population growth, and depreciation.

The core difference is simple: in Simple Interest (SI), interest is calculated only on the principal throughout the period. In Compound Interest (CI), interest is calculated on the principal plus accumulated interest—interest earns interest. Most exam questions test your ability to apply formulas quickly, find the difference between SI and CI, or work backwards to find principal, rate, or time.

Focus areas for HSSC CET include: basic SI/CI calculations, finding the difference between CI and SI for 2–3 years, half-yearly/quarterly compounding, and real-world applications like population growth and depreciation.


Key Concepts

  • Principal (P): The initial amount of money borrowed or invested.
  • Rate (R): The percentage of interest charged per time period (usually per annum).
  • Time (T/n): The duration for which money is borrowed or invested.
  • Simple Interest: Interest remains constant each year because it's always calculated on the original principal only.
  • Compound Interest: Interest is added to principal at the end of each compounding period, so next period's interest is higher.
  • Compounding Frequency: Interest may be compounded annually, half-yearly (2 times/year), quarterly (4 times/year), or monthly (12 times/year).
  • Amount (A): Total money at the end = Principal + Interest.
  • CI and SI are equal for the first year when compounding is annual and rate remains constant.

Formulas / Key Facts

Simple Interest:

  • SI = (P × R × T) / 100
  • Amount (A) = P + SI = P(1 + RT/100)

Compound Interest:

  • Amount = P × (1 + R/100)ⁿ, where n = number of years
  • CI = Amount – P = P × [(1 + R/100)ⁿ – 1]

Half-yearly Compounding:

  • Rate becomes R/2, Time becomes 2n
  • Amount = P × (1 + R/200)^(2n)

Quarterly Compounding:

  • Rate becomes R/4, Time becomes 4n
  • Amount = P × (1 + R/400)^(4n)

Difference between CI and SI:

  • For 2 years: CI – SI = P × (R/100)²
  • For 3 years: CI – SI = P × (R/100)² × (3 + R/100)

Population/Growth Formula:

  • After n years: P × (1 + R/100)ⁿ (for growth)
  • After n years: P × (1 – R/100)ⁿ (for depreciation)

When Amount doubles:

  • Under SI: T = 100/R years
  • Under CI: Use (1 + R/100)ⁿ = 2

Key Fact: At the same rate, CI > SI for any period greater than 1 year.


Worked Examples

Example 1: Basic Simple Interest

Find the SI on ₹8,000 at 12% per annum for 3 years.

SI = (P × R × T) / 100 SI = (8000 × 12 × 3) / 100 SI = 288000 / 100 = ₹2,880

Amount = 8000 + 2880 = ₹10,880


Example 2: Compound Interest Calculation

Find CI on ₹5,000 at 10% per annum for 2 years, compounded annually.

Amount = P × (1 + R/100)ⁿ Amount = 5000 × (1 + 10/100)² Amount = 5000 × (1.1)² Amount = 5000 × 1.21 = ₹6,050

CI = 6050 – 5000 = ₹1,050


Example 3: Difference between CI and SI for 2 years

The difference between CI and SI on a sum at 5% for 2 years is ₹20. Find the sum.

Using formula: CI – SI = P × (R/100)² 20 = P × (5/100)² 20 = P × (1/400) P = 20 × 400 = ₹8,000


Example 4: Half-yearly Compounding

Find the amount on ₹10,000 at 8% per annum for 1 year, compounded half-yearly.

Rate per half-year = 8/2 = 4% Number of periods = 2

Amount = 10000 × (1 + 4/100)² Amount = 10000 × (1.04)² Amount = 10000 × 1.0816 = ₹10,816


Example 5: Population Growth

The population of a town is 50,000. It increases by 10% in the first year and 20% in the second year. Find the population after 2 years.

After Year 1: 50000 × (1 + 10/100) = 50000 × 1.1 = 55,000 After Year 2: 55000 × (1 + 20/100) = 55000 × 1.2 = 66,000

Final population = 66,000


Common Mistakes

  • Forgetting to convert time to years: If time is given in months, divide by 12. Many students use months directly in the formula. → Correct fix: Always convert time to years before applying SI/CI formulas.
  • Using annual rate for half-yearly problems: When compounding is half-yearly, you must halve the rate and double the time period. → Correct fix: For half-yearly, use R/2 and 2n; for quarterly, use R/4 and 4n.
  • Confusing CI formula with Amount formula: Students sometimes calculate Amount but report it as CI. → Correct fix: CI = Amount – Principal. Always subtract principal to get interest.
  • Applying CI–SI difference formula for 3 years incorrectly: The 2-year formula P(R/100)² doesn't work for 3 years. → Correct fix: For 3 years, use P × (R/100)² × (3 + R/100).
  • Ignoring different rates for different years: When rates vary each year, you cannot use standard CI formula. → Correct fix: Calculate year by year: Amount after Year 1 becomes Principal for Year 2.

Quick Reference

  • SI = (P × R × T) / 100 — interest on original principal only
  • CI Amount = P × (1 + R/100)ⁿ — interest on interest
  • CI – SI (2 years) = P × (R/100)² — quick trick for exam
  • Half-yearly: rate ÷ 2, time × 2
  • Doubling time under SI = 100/R years
  • For growth use (1 + R/100)ⁿ; for depreciation use (1 – R/100)ⁿ

Drafted with AI from Shishya's syllabus outline for this exam · Reviewed by a person: not yet · Report an error

You read the notes — now try one

A sum of Rs 8,000 is invested at 10% per annum simple interest for 3 years. What is the simple interest earned?

Tap an option to check your answer.

👥 Study this together

Invite your prep group — read the same notes, then discuss doubts in this topic's shared room.

Invite to study

Need more? Ask Shishya

Shishya is your personal tutor for this topic. Pick a starter or open a free chat.

Open Shishya tutor →

Practice this topic

Take a full mock →
  • Q1 · Simple and Compound Interest · EASY

    A sum of Rs 8,000 is invested at 10% per annum simple interest for 3 years. What is the simple interest earned?

  • Q2 · Simple and Compound Interest · MEDIUM

    A person borrows Rs 12,000 at 12% per annum simple interest. After how many years will the amount become Rs 16,320?

  • Q3 · Simple and Compound Interest · MEDIUM

    A sum of Rs 5,000 is invested at 8% per annum compound interest compounded annually. What will be the amount after 2 years?

  • Q4 · Simple and Compound Interest · HARD

    The difference between compound interest and simple interest on a sum of Rs 10,000 for 2 years at 10% per annum is:

  • Q5 · Simple and Compound Interest · EASY

    At what rate percent per annum will ₹8,000 amount to ₹10,400 in 3 years at simple interest?

Ask Shishya to explain these →

Notes generated on 11 Sept 2026