AP EAMCET · Previous year papers · 2021
AP EAMCET 2021 previous year paper practice · PYQ-pattern set
15 PYQ-pattern questions modelled on the 2021 paper (which had 160) · 180 min
Every question here is freshly worded in the pattern of the 2021 paper — same topics, style and difficulty — not the original questions, which Shishya does not reproduce.
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Showing 10 of the 15 PYQ-pattern questions in this set — freshly worded in that year's pattern, not the original questions. Answers and solutions open under each question.
Q1 · Binomial Theorem
The middle term in the expansion of (x - 2y)⁶ is
- A. -160x³y³
- B. -320x³y³
- C. 160x³y³
- D. 320x³y³
Answer and solution
Answer: A
For (x-2y)^6, n=6, middle term is 4th term (r=3): C(6,3) x^3 (-2y)^3 = 20 · x^3 · (-8y^3) = -160 x^3 y^3.
Q2 · Probability
Two dice are thrown simultaneously. The probability that the sum of the numbers on the two dice is at least 10 is
- A. 1/6
- B. 1/9
- C. 5/36
- D. 1/12
Answer and solution
Answer: A
Total outcomes = 36. Favorable outcomes (sum ≥ 10): (4,6), (5,5), (5,6), (6,4), (6,5), (6,6) = 6. Probability = 6/36 = 1/6.
Q3 · Direction Cosines and Direction Ratios
If a line makes angles π/4, π/3 and θ (where 0 < θ < π/2) with the positive directions of X, Y and Z axes respectively, then the value of θ is
- A. π/6
- B. π/4
- C. π/3
- D. 5π/12
Answer and solution
Answer: C
Direction cosines satisfy cos²α+cos²β+cos²γ=1. With α=π/4, cos²=1/2; β=π/3, cos²=1/4. So cos²θ=1-3/4=1/4, cosθ=1/2, giving θ=π/3.
Q4 · Ellipse
The equation of the ellipse with foci on the x-axis, centre at origin, major axis of length 10 and minor axis of length 8 is
- A. x²/25 + y²/16 = 1
- B. x²/16 + y²/25 = 1
- C. x²/100 + y²/64 = 1
- D. x²/50 + y²/32 = 1
Answer and solution
Answer: A
Major axis length 2a = 10 gives a = 5, and minor axis length 2b = 8 gives b = 4. Since foci are on x-axis, the equation is x²/a² + y²/b² = 1, which is x²/25 + y²/16 = 1.
Q5 · Definite Integration
The value of ∫₀^(π/4) sec²(x) dx is:
- A. 0
- B. 1
- C. π/4
- D. √2
Answer and solution
Answer: B
∫ sec²(x) dx = tan(x). Evaluating from 0 to π/4: tan(π/4) - tan(0) = 1 - 0 = 1.
Q6 · Units and Measurements
In a system where unit of length is 5 m and unit of time is 4 s, the unit of force will be equivalent to:
- A. 0.3125 N
- B. 1.25 N
- C. 3.2 N
- D. 80 N
Answer and solution
Answer: A
Force has dimension [MLT⁻²]. If L' = 5L and T' = 4T, then F' = M'L'T'⁻² = M(5L)(4T)⁻² = (5/16)MLT⁻² = (5/16)F. Thus 1 new unit = 5/16 N = 0.3125 N.
Q7 · System of Particles and Rotational Motion
A uniform disc of radius 0.5 m and mass 10 kg is rotating about an axis passing through its center and perpendicular to its plane with an angular velocity of 6 rad/s. What is its rotational kinetic energy?
- A. 22.5 J
- B. 30 J
- C. 45 J
- D. 60 J
Answer and solution
Answer: A
Moment of inertia I = ½MR² = ½(10)(0.5)² = 1.25 kg·m². Rotational KE = ½Iω² = ½(1.25)(6)² = 22.5 J.
Q8 · Work, Energy and Power
A machine lifts a load of 500 kg to a height of 20 m in 25 seconds. What is the power developed by the machine? (Take g = 10 m/s²)
- A. 2 kW
- B. 4 kW
- C. 5 kW
- D. 10 kW
Answer and solution
Answer: B
Work done W = mgh = 500×10×20 = 100000 J. Power P = W/t = 100000/25 = 4000 W = 4 kW.
Q9 · Waves
A tuning fork of frequency 512 Hz is used to produce resonance in a resonance tube experiment. The first resonance is observed at 16.5 cm and the second at 50.5 cm. The velocity of sound in air is
- A. 330 m/s
- B. 340 m/s
- C. 348 m/s
- D. 356 m/s
Answer and solution
Answer: C
The distance between first and second resonance = λ/2 = (50.5 - 16.5) = 34 cm. So λ = 68 cm = 0.68 m. Velocity v = fλ = 512 × 0.68 = 348.16 m/s ≈ 348 m/s.
Q10 · Thermodynamics
In a Carnot engine, the temperature of the source is 400 K and efficiency is 40%. To increase the efficiency to 50%, keeping the sink temperature constant, the source temperature should be
- A. 450 K
- B. 480 K
- C. 500 K
- D. 520 K
Answer and solution
Answer: B
Efficiency η = 1 - T₂/T₁. For η = 0.4, we have 0.4 = 1 - T₂/400, giving T₂ = 240 K. For η = 0.5, we need 0.5 = 1 - 240/T₁', so T₁' = 240/0.5 = 480 K.
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