CG TET · Mathematics (Paper I)

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Percentage

Percentage calculations and applications.

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Percentage — Study Notes for CG TET Paper I

Overview

Percentage is one of the most practical and frequently tested topics in CG TET Paper I Mathematics. It forms the foundation for understanding profit-loss, simple interest, and data interpretation — all of which appear in the syllabus. For a primary school teacher, mastery of percentage is essential because it connects classroom mathematics to real-life situations like discounts, marks calculation, and population data.

Questions typically test basic conversion (fraction to percentage), finding percentage of a quantity, percentage increase/decrease, and simple word problems. The pedagogy section may also ask how to teach percentage using real-life examples from the Chhattisgarh context — local market prices, agricultural yield data, or school attendance figures.

Your goal: be fluent in quick mental calculations, understand the concept deeply enough to explain it to Class 4–5 students, and avoid common calculation traps.


Key Concepts

  • Definition: Percent means "per hundred." Writing 25% means 25 out of 100, or 25/100 = 0.25.
  • Fraction-Percentage-Decimal Triangle: Any fraction can be written as a percentage by multiplying by 100. Any percentage can be written as a decimal by dividing by 100. Example: 3/4 = 75% = 0.75.
  • Base Value Concept: When we say "20% of 150," the number 150 is the base. Always identify the base clearly in word problems.
  • Percentage Change: Increase or decrease is always calculated on the original (initial) value, not the new value.
  • Successive Percentage: When two percentages apply one after another, they don't simply add. You must apply them step by step.
  • Reversibility: If a value increases by x%, to restore it you don't decrease by x%. The reverse percentage is different because the base changes.
  • Percentage Points vs Percentage: If pass percentage rises from 60% to 75%, the increase is 15 percentage points, but the percentage increase is (15/60) × 100 = 25%.

Formulas / Key Facts

ConceptFormula
Percentage of a numberx% of N = (x/100) × N
Fraction to percentage(a/b) × 100 %
Percentage to fractionx% = x/100 (simplify)
Percentage increase[(New − Old)/Old] × 100
Percentage decrease[(Old − New)/Old] × 100
New value after increaseOld × (1 + x/100)
New value after decreaseOld × (1 − x/100)
Successive change (a% then b%)Net effect = a + b + (ab/100) %
Reverse of x% increaseDecrease by [x/(100+x)] × 100 %
Reverse of x% decreaseIncrease by [x/(100−x)] × 100 %

Must-remember fraction-percentage equivalents:

  • 1/2 = 50%, 1/4 = 25%, 3/4 = 75%
  • 1/5 = 20%, 2/5 = 40%, 3/5 = 60%, 4/5 = 80%
  • 1/8 = 12.5%, 1/3 = 33.33%, 2/3 = 66.67%
  • 1/6 = 16.67%, 1/10 = 10%, 1/20 = 5%

Worked Examples

Example 1: Finding percentage of a quantity

Problem: A farmer in Raipur harvested 450 quintals of paddy. If 18% was damaged due to rain, how much paddy was damaged?

Solution:

  • Damaged paddy = 18% of 450
  • = (18/100) × 450
  • = 18 × 4.5
  • = 81 quintals

Answer: 81 quintals


Example 2: Percentage increase

Problem: The population of a village was 12,000 in 2020. It increased to 13,800 in 2023. Find the percentage increase.

Solution:

  • Increase = 13,800 − 12,000 = 1,800
  • Percentage increase = (Increase/Original) × 100
  • = (1800/12000) × 100
  • = (1800 × 100)/12000
  • = 15%

Answer: 15% increase


Example 3: Successive percentage change

Problem: The price of rice increased by 20% in the first month, then decreased by 10% in the second month. What is the net percentage change?

Solution: Using the formula: Net = a + b + (ab/100)

  • Here a = +20, b = −10
  • Net = 20 + (−10) + (20 × −10)/100
  • = 20 − 10 − 2
  • = 8%

Verification: Let original price = ₹100

  • After 20% increase = ₹120
  • After 10% decrease on 120 = 120 − 12 = ₹108
  • Net change = ₹8 on ₹100 = 8%

Answer: Net increase of 8%


Example 4: Reverse percentage

Problem: After a 25% increase, the salary of a teacher became ₹31,250. What was the original salary?

Solution:

  • Let original salary = x
  • After 25% increase: x × (1 + 25/100) = 31,250
  • x × 1.25 = 31,250
  • x = 31,250 ÷ 1.25
  • x = 25,000

Answer: ₹25,000


Common Mistakes

  1. Calculating percentage change on the wrong base
    • Wrong: "Price went from ₹80 to ₹100, so increase = 20/100 = 20%"
    • Correct: Base is the original value (₹80), so increase = 20/80 × 100 = 25%
  2. Adding successive percentages directly
    • Wrong: "20% increase then 20% decrease = no change"
    • Correct: Apply the formula — net effect = 20 − 20 + (20 × −20)/100 = −4%. There is a 4% decrease.
  3. Confusing "percentage of" with "percentage more than"
    • "A is 25% of B" means A = 0.25B
    • "A is 25% more than B" means A = 1.25B
  4. Forgetting to convert percentage to decimal/fraction before multiplying
    • Wrong: 15% of 200 = 15 × 200 = 3000
    • Correct: 15% of 200 = (15/100) × 200 = 30
  5. Using the new value as base for reverse calculation
    • Wrong: "If price increased by 20%, to get original, decrease new price by 20%"
    • Correct: To reverse a 20% increase, decrease by (20/120) × 100 = 16.67%

Quick Reference

  • Percent = Per Hundred: Always think "out of 100"
  • Conversion shortcut: To find x% of N, move decimal two places left in x, then multiply by N
  • Percentage change base: Always use the ORIGINAL value as denominator
  • Successive change formula: a + b + (ab/100) — memorize this for quick calculation
  • Common trap: 50% increase followed by 50% decrease ≠ 0% change (actually −25%)
  • Teaching tip for CG TET pedagogy: Use local examples — percentage of tribal population, percentage of forest cover in Bastar, discount at local haat bazaar

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If a school has 800 students and 35% of them are girls, how many boys are there in the school?

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  • Q1 · Percentage · EASY

    If a school has 800 students and 35% of them are girls, how many boys are there in the school?

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Notes generated on 27 Jun 2026