SOF NSO · Science

Newton's three laws, inertia, momentum and conservation of momentum.

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Force and Laws of Motion — Study Notes

Overview

Force and Laws of Motion is a cornerstone topic in mechanics that appears prominently in SOF NSO Class 9 and Class 10 papers. This chapter explains why objects move the way they do and introduces Newton's three laws of motion, which govern all motion in our everyday world—from a cricket ball being hit to a rocket launching into space.

Students must master three core ideas: (1) inertia (why objects resist changes in motion), (2) momentum (quantity of motion), and (3) action-reaction pairs. Strong conceptual clarity on the laws, combined with numerical fluency in momentum conservation problems, is essential for scoring well.

The topic builds directly on Class 9 Motion, so ensure you're comfortable with velocity, acceleration and equations of motion before diving deep here.

Key Concepts

  • Force is a push or pull that changes or tends to change the state of rest or uniform motion of an object. SI unit: Newton (N). 1 N = 1 kg·m/s².
  • Inertia is the tendency of an object to resist changes in its state of motion. Mass is the measure of inertia—heavier objects have more inertia.
  • Newton's First Law (Law of Inertia): An object at rest stays at rest, and an object in uniform motion stays in uniform motion, unless acted upon by an external unbalanced force.
  • Newton's Second Law: The rate of change of momentum is directly proportional to the applied force and occurs in the direction of the force. Mathematically: F = ma (when mass is constant).
  • Newton's Third Law: For every action, there is an equal and opposite reaction. Forces always occur in pairs acting on different objects.
  • Momentum (p) is the product of mass and velocity: p = mv. SI unit: kg·m/s. Momentum is a vector quantity.
  • Law of Conservation of Momentum: In an isolated system with no external forces, the total momentum before an event equals the total momentum after the event. Critical for collision and explosion problems.
  • Balanced forces produce no change in motion (zero net force). Unbalanced forces cause acceleration.

Formulas / Key Facts

  • Force: F = ma (mass × acceleration)
  • Momentum: p = mv (mass × velocity)
  • Newton's Second Law (general form): F = (m·v − m·u) / t = m(v − u)/t = ma
  • Alternative form of Second Law: F = Δp / Δt (force equals rate of change of momentum)
  • Conservation of Momentum (two-body collision): m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂, where u = initial velocity, v = final velocity
  • Recoil velocity formula (gun-bullet): If bullet mass m₁, velocity v₁; gun mass m₂, recoil velocity v₂, then: m₁v₁ + m₂v₂ = 0 (starting from rest)
  • 1 Newton: The force required to give a 1 kg mass an acceleration of 1 m/s²
  • Weight: W = mg (force due to gravity; g ≈ 10 m/s² on Earth)

Worked Examples

Example 1: Applying Newton's Second Law A force of 20 N acts on a body of mass 5 kg. Find the acceleration produced.

Solution: Given: F = 20 N, m = 5 kg Using F = ma 20 = 5 × a a = 20/5 = 4 m/s²


Example 2: Momentum Change A cricket ball of mass 150 g moving at 20 m/s is hit back in the opposite direction at 30 m/s. Calculate the change in momentum.

Solution: Mass m = 150 g = 0.15 kg Initial velocity u = +20 m/s (take as positive direction) Final velocity v = −30 m/s (opposite direction) Initial momentum p₁ = mu = 0.15 × 20 = 3 kg·m/s Final momentum p₂ = mv = 0.15 × (−30) = −4.5 kg·m/s Change in momentum Δp = p₂ − p₁ = −4.5 − 3 = −7.5 kg·m/s Magnitude of change = 7.5 kg·m/s


Example 3: Conservation of Momentum (Recoil) A rifle of mass 4 kg fires a bullet of mass 50 g with a velocity of 200 m/s. Find the recoil velocity of the rifle.

Solution: Bullet: m₁ = 50 g = 0.05 kg, v₁ = 200 m/s Rifle: m₂ = 4 kg, v₂ = ? Initial momentum = 0 (both at rest) By conservation of momentum: m₁v₁ + m₂v₂ = 0 0.05 × 200 + 4 × v₂ = 0 10 + 4v₂ = 0 v₂ = −10/4 = −2.5 m/s Negative sign indicates rifle moves backward (recoil). Recoil speed = 2.5 m/s

Common Mistakes

  • Confusing mass and weight: Mass is the amount of matter (kg), weight is the force due to gravity (N). Weight = mg, not just m. Always use weight when asked for force.
  • Ignoring direction in momentum problems: Momentum is a vector. In conservation problems, assign +/− signs to velocities carefully. Opposite directions must have opposite signs.
  • Thinking Third Law pairs act on the same object: Action and reaction act on different objects. Example: When you push a wall, you exert force on the wall (action) and the wall exerts force on you (reaction)—not both on you.
  • Assuming F = ma applies when mass changes: The general form F = Δp/Δt must be used when mass varies (e.g., rocket propulsion, sand falling on a conveyor). For constant mass, F = ma is valid.
  • Forgetting units conversion: Always convert grams to kilograms, cm/s to m/s before applying formulas. A mass of 500 g is 0.5 kg, not 500 kg!

Quick Reference

  • Inertia ∝ mass: More mass → more resistance to change in motion.
  • F = ma: Force causes acceleration; zero net force → zero acceleration (uniform motion or rest).
  • Momentum p = mv: Larger mass or higher velocity → larger momentum.
  • Newton's Third Law: Forces exist in pairs on different objects; equal magnitude, opposite direction.
  • Conservation of Momentum: Total momentum before = Total momentum after (isolated system, no external forces).
  • Recoil problems: Use m₁v₁ + m₂v₂ = 0 when starting from rest; momentum is conserved, object moves backward.

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A cricket ball of mass 0.15 kg moving with a velocity of 20 m/s is stopped by a fielder in 0.1 seconds. What is the magnitude of the force applied by the fielder?

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  • Q1 · Force and Laws of Motion · EASY

    A cricket ball of mass 0.15 kg moving with a velocity of 20 m/s is stopped by a fielder in 0.1 seconds. What is the magnitude of the force applied by the fielder?

  • Q2 · Force and Laws of Motion · EASY

    A passenger in a moving bus falls forward when the bus suddenly stops. Which of Newton's laws explains this phenomenon?

  • Q3 · Force and Laws of Motion · MEDIUM

    Two objects of masses 2 kg and 3 kg are moving in the same direction with velocities 4 m/s and 2 m/s respectively. They collide and stick together. What is their common velocity after collision?

  • Q4 · Force and Laws of Motion · MEDIUM

    A force of 50 N acts on a body and produces an acceleration of 5 m/s². If the force is increased to 80 N, what will be the new acceleration produced in the body?

  • Q5 · Force and Laws of Motion · HARD

    A gun of mass 5 kg fires a bullet of mass 20 g with a velocity of 400 m/s. What is the recoil velocity of the gun?

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Notes generated on 10 May 2026