RRB Group D · Mathematics

Time and Distance

Trains, boats and streams, relative and average speed.

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Time and Distance — Study Notes

Overview

The questions test your ability to connect speed, time and distance using the fundamental relationship: Distance = Speed × Time. Mastery of this topic is non-negotiable because it directly links to real-world railway operations—trains meeting, overtaking, crossing platforms, and relative motion.

The RRB Group D syllabus explicitly includes trains, boats and streams, and relative and average speed. You must be comfortable with unit conversions (km/h ↔ m/s), understand how speeds add or subtract in relative motion, and apply the distance formula in various contexts. Problems range from straightforward direct applications to multi-step word problems involving two moving objects. Strong command here also aids in solving Time-Speed-Work problems, making this a foundational quantitative skill.

Focus on clarity in setting up equations, careful unit handling, and recognizing problem patterns (train crossing, boats upstream/downstream, relative speed). Practice is essential—solve 30–40 problems to internalize the formulas and shortcuts.

Key Concepts

  • Fundamental Relationship: Distance = Speed × Time. Rearrange to find any one quantity if two are known: Speed = Distance/Time, Time = Distance/Speed.
  • Unit Conversion: 1 km/h = 5/18 m/s and 1 m/s = 18/5 km/h. Always check units in word problems and convert as needed before calculation.
  • Relative Speed (same direction): When two objects move in the same direction, their relative speed = |Speed₁ - Speed₂|. Used when one overtakes the other.
  • Relative Speed (opposite direction): When two objects move towards each other, their relative speed = Speed₁ + Speed₂. Used when they meet or cross.
  • Average Speed: For a journey with different speeds over equal distances, Average Speed = Total Distance / Total Time, NOT the arithmetic mean of speeds.
  • Trains Crossing: When a train crosses a stationary object (pole, man), distance = length of train. When crossing a platform or bridge, distance = length of train + length of platform/bridge.
  • Boats and Streams: Downstream speed = speed of boat in still water + speed of stream. Upstream speed = speed of boat in still water - speed of stream. Use these to find boat speed and stream speed separately.
  • Meeting and Chasing: If two objects start simultaneously and move towards each other, time to meet = distance between them / (sum of speeds). If one chases the other, time to meet = initial gap / (difference of speeds).

Formulas / Key Facts

  1. Basic Formula: Distance = Speed × Time; Speed = Distance / Time; Time = Distance / Speed.
  2. km/h to m/s: Multiply by 5/18. Example: 72 km/h = 72 × 5/18 = 20 m/s.
  3. m/s to km/h: Multiply by 18/5. Example: 25 m/s = 25 × 18/5 = 90 km/h.
  4. Relative Speed (opposite): S_rel = S₁ + S₂.
  5. Relative Speed (same): S_rel = |S₁ - S₂|.
  6. Train Crossing Pole/Man: Time = Length of train / Speed of train.
  7. Train Crossing Platform: Time = (Length of train + Length of platform) / Speed of train.
  8. Two Trains Crossing (opposite directions): Time = (L₁ + L₂) / (S₁ + S₂).
  9. Two Trains Crossing (same direction): Time = (L₁ + L₂) / |S₁ - S₂|.
  10. Downstream Speed: S_d = S_boat + S_stream.
  11. Upstream Speed: S_u = S_boat - S_stream.
  12. Boat Speed in Still Water: S_boat = (S_d + S_u) / 2.
  13. Stream Speed: S_stream = (S_d - S_u) / 2.
  14. Average Speed (two equal distances at different speeds): Avg Speed = (2 × S₁ × S₂) / (S₁ + S₂).
  15. Distance between two objects meeting: If starting distance D apart, moving towards each other at speeds S₁ and S₂, they meet after time = D / (S₁ + S₂).

Worked Examples

Example 1: Basic Speed Calculation A train travels 180 km in 3 hours. Find its speed in m/s.

Solution: Speed in km/h = Distance / Time = 180 / 3 = 60 km/h. Convert to m/s: 60 × 5/18 = 300/18 = 16.67 m/s.

Example 2: Train Crossing a Platform A 150 m long train crosses a 250 m platform in 20 seconds. Find the speed of the train in km/h.

Solution: Total distance = Length of train + Length of platform = 150 + 250 = 400 m. Speed = Distance / Time = 400 / 20 = 20 m/s. Convert to km/h: 20 × 18/5 = 72 km/h.

Example 3: Boats and Streams A boat travels downstream 40 km in 2 hours and upstream 30 km in 3 hours. Find the speed of the boat in still water and the speed of the stream.

Solution: Downstream speed S_d = 40 / 2 = 20 km/h. Upstream speed S_u = 30 / 3 = 10 km/h. Boat speed in still water = (S_d + S_u) / 2 = (20 + 10) / 2 = 15 km/h. Stream speed = (S_d - S_u) / 2 = (20 - 10) / 2 = 5 km/h.

Example 4: Relative Speed – Meeting Two trains 200 m and 150 m long are moving towards each other at 54 km/h and 36 km/h. In how much time will they cross each other?

Solution: Convert speeds: 54 km/h = 54 × 5/18 = 15 m/s; 36 km/h = 36 × 5/18 = 10 m/s. Relative speed (opposite) = 15 + 10 = 25 m/s. Total distance to cover = 200 + 150 = 350 m. Time = 350 / 25 = 14 seconds.

Example 5: Average Speed A person travels the first half of a distance at 40 km/h and the second half at 60 km/h. Find the average speed for the entire journey.

Solution: Use the formula for average speed over equal distances: Avg Speed = (2 × S₁ × S₂) / (S₁ + S₂) = (2 × 40 × 60) / (40 + 60) = 4800 / 100 = 48 km/h. (Not 50 km/h, which is the arithmetic mean!)

Common Mistakes

  1. Mixing units: Calculating distance in km but time in seconds without converting speed to m/s. Always ensure all quantities are in compatible units before applying formulas.
  2. Wrong relative speed direction: Adding speeds when objects move in the same direction (should subtract), or subtracting when they move opposite (should add). Remember: opposite → add, same → subtract.
  3. Averaging speeds incorrectly: Taking the arithmetic mean (S₁ + S₂)/2 instead of using the harmonic mean formula (2S₁S₂)/(S₁ + S₂) for equal distances. Average speed depends on time spent, not just speeds.
  4. Forgetting train length: When a train crosses a platform, students often use only the platform length. Correct distance = train length + platform length.
  5. Boat speed confusion: Mixing up downstream and upstream. Remember: downstream is WITH the current (faster), upstream is AGAINST the current (slower). Always S_d > S_u.

Quick Reference

  • Distance = Speed × Time — The mother formula. Rearrange as needed.
  • 1 km/h = 5/18 m/s; 1 m/s = 18/5 km/h — Memorize these conversions cold.
  • Relative speed: opposite → add; same → subtract — Critical for train and meeting problems.
  • Train crossing: add lengths — Train + platform or train + train.
  • Boats: downstream = boat + stream; upstream = boat - stream — Then solve for unknowns.
  • Average speed ≠ arithmetic mean — Use (2S₁S₂)/(S₁ + S₂) for equal distances.

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A train travels 120 km in 2 hours. What is its speed in metres per second?

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  • Q1 · Time and Distance · EASY

    A train travels 120 km in 2 hours. What is its speed in metres per second?

  • Q2 · Time and Distance · MEDIUM

    A boat travels 36 km upstream in 4 hours and the same distance downstream in 3 hours. What is the speed of the stream in km/h?

  • Q3 · Time and Distance · MEDIUM

    Two trains of lengths 150 m and 180 m are running in opposite directions at speeds of 54 km/h and 72 km/h respectively. In how many seconds will they completely cross each other?

  • Q4 · Time and Distance · MEDIUM

    A man covers a certain distance at 40 km/h and returns to the starting point at 60 km/h. What is his average speed for the entire journey?

  • Q5 · Time and Distance · HARD

    A train 240 metres long is running at 90 km/h. It crosses a platform of length 360 metres. How much time in seconds does it take to cross the platform completely?

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Notes generated on 10 May 2026