KAR TET · Mathematics and Science (Paper II)

More Karnataka government exams →

Physics — Light

Reflection, refraction, lenses, mirrors and image formation.

Share with your prep group:WhatsApp

Test yourself on Physics — Light

Practice questions for KAR TET on this topic with instant answers — no signup.

Take the quick quiz →

Physics — Light

Overview

Light is a fundamental topic in the KAR TET Paper II Science section, bridging everyday observation with core physics principles. Questions typically test your understanding of how light behaves when it strikes mirrors and passes through lenses—reflection and refraction—and how images form in optical devices.

Mastery requires you to visualize ray diagrams, apply mirror and lens formulas, and predict image characteristics (real/virtual, magnified/diminished, erect/inverted). Beyond the content, expect 1–2 pedagogy-linked questions on how to teach these concepts using experiments and demonstrations.

Students who score well here can quickly identify mirror/lens type from a problem, sketch the relevant ray diagram mentally, and apply sign conventions correctly.


Key Concepts

  • Light travels in straight lines (rectilinear propagation), which explains shadows, eclipses and pinhole cameras.
  • Reflection is the bouncing back of light from a surface; it follows two laws: (i) angle of incidence = angle of reflection, (ii) incident ray, reflected ray and normal lie in the same plane.
  • Refraction is the bending of light when it passes from one medium to another due to a change in speed; governed by Snell's law.
  • Refractive index (n) = speed of light in vacuum / speed of light in medium; higher n means denser medium and more bending toward the normal.
  • Mirrors are of two main types: plane (flat surface, virtual and same-size image) and spherical (concave or convex, curved surface).
  • Lenses are transparent refracting devices: convex (converging) and concave (diverging).
  • Real images are formed by actual convergence of rays (can be caught on screen); virtual images are formed where rays appear to diverge from (cannot be caught on screen).
  • Sign convention (New Cartesian): distances measured from the optical centre/pole; distances in the direction of incident light are positive; heights above principal axis are positive.

Formulas / Key Facts

ConceptFormula / Fact
Laws of Reflection∠i = ∠r; incident ray, reflected ray, normal in same plane
Snell's Lawn₁ sin i = n₂ sin r (or n = sin i / sin r for air-to-medium)
Mirror Formula1/v + 1/u = 1/f
Lens Formula1/v − 1/u = 1/f
Magnification (mirror)m = −v/u = h'/h
Magnification (lens)m = v/u = h'/h
Power of LensP = 1/f (f in metres); unit is dioptre (D)
Relation: R and ff = R/2 (for spherical mirrors)
Critical Anglesin C = 1/n (total internal reflection occurs when i > C, light going from denser to rarer)
Speed of light in vacuum≈ 3 × 10⁸ m/s

Worked Examples

Example 1 — Mirror Formula (Concave Mirror)

Problem: An object is placed 30 cm in front of a concave mirror of focal length 15 cm. Find the image position and nature.

Solution:

Using sign convention: u = −30 cm, f = −15 cm (concave mirror, focus in front).

Apply mirror formula: 1/v + 1/u = 1/f 1/v + 1/(−30) = 1/(−15) 1/v = −1/15 + 1/30 = (−2 + 1)/30 = −1/30 v = −30 cm

Image is at 30 cm in front of mirror (same side as object).

Magnification m = −v/u = −(−30)/(−30) = −1

Nature: Real (v negative, same side), inverted (m negative), same size (|m| = 1).


Example 2 — Refraction and Snell's Law

Problem: A ray of light passes from air into glass (n = 1.5) at an angle of incidence 30°. Find the angle of refraction.

Solution:

n = sin i / sin r 1.5 = sin 30° / sin r = 0.5 / sin r sin r = 0.5 / 1.5 = 1/3 ≈ 0.333 r = sin⁻¹(0.333) ≈ 19.5°

The refracted ray bends toward the normal as light enters a denser medium.


Example 3 — Lens and Power

Problem: A convex lens has a focal length of 25 cm. What is its power?

Solution:

Convert f to metres: f = 0.25 m P = 1/f = 1/0.25 = +4 D

Positive power indicates a converging lens.


Common Mistakes

Wrong ThinkingCorrect Fix
Forgetting sign convention and using all positive values → wrong image position/nature.Always apply New Cartesian sign convention; concave mirror f is negative, convex lens f is positive.
Confusing mirror formula (1/v + 1/u = 1/f) with lens formula (1/v − 1/u = 1/f).Remember: "Mirror has a plus, Lens has a minus" in the formula.
Believing virtual images are always smaller; real images are always larger.Size depends on object position relative to focus; virtual images can be magnified (e.g., magnifying glass).
Mixing up convex mirror and convex lens behaviour.Convex mirror diverges light (virtual, diminished image); convex lens converges light (can form real or virtual image).
Ignoring units when calculating power → answer off by factor of 100.Focal length must be in metres for power in dioptres.

Quick Reference

  1. Concave mirror uses: shaving mirrors, dentist mirrors, headlights, solar furnaces.
  2. Convex mirror uses: rear-view mirrors (wider field of view).
  3. Convex lens uses: magnifying glass, camera, projector, human eye correction (hypermetropia).
  4. Concave lens uses: correction of myopia (short-sightedness).
  5. Total internal reflection: occurs only when light travels from denser to rarer medium and angle of incidence exceeds critical angle.
  6. Image by plane mirror: always virtual, erect, same size, laterally inverted, at same distance behind mirror as object is in front.

Drafted with AI from Shishya's syllabus outline for this exam · Reviewed by a person: not yet · Report an error

You read the notes — now try one

A concave mirror has a focal length of 15 cm. An object is placed at a distance of 30 cm from the mirror. Where will the image be formed?

Tap an option to check your answer.

👥 Study this together

Invite your prep group — read the same notes, then discuss doubts in this topic's shared room.

Invite to study

Need more? Ask Shishya

Shishya is your personal tutor for this topic. Pick a starter or open a free chat.

Open Shishya tutor →

Practice this topic

Take a full mock →
  • Q1 · Physics — Light · EASY

    A concave mirror has a focal length of 15 cm. An object is placed at a distance of 30 cm from the mirror. Where will the image be formed?

Ask Shishya to explain these →

Notes generated on 27 Jun 2026