JTET · Mathematics and Science (Paper II)

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Trigonometry

Trigonometric ratios and identities.

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Trigonometry — Study Notes for JTET Paper II

Overview

Trigonometry forms a crucial component of the Mathematics section in JTET Paper II, designed for teachers aspiring to teach Classes VI–VIII. This topic connects geometry with algebra through the study of relationships between angles and sides of triangles. For the upper-primary level, the focus remains on right-angled triangles and the six fundamental trigonometric ratios.

Understanding trigonometry is essential not just for solving direct problems but also for its applications in height and distance problems, which frequently appear in competitive examinations. As a prospective mathematics teacher, you must master both the conceptual understanding and the problem-solving techniques to effectively teach these concepts to students.

The JTET syllabus specifically mentions trigonometric ratios and identities, so expect questions on ratio calculations, identity proofs, and simple applications. Building a strong foundation in the standard angles (0°, 30°, 45°, 60°, 90°) and the eight fundamental identities is non-negotiable for success.

Key Concepts

  • Trigonometric ratios are defined only for acute angles in a right-angled triangle, relating the sides (perpendicular, base, hypotenuse) to the angle in question.
  • Six ratios exist in complementary pairs: sin-cos, tan-cot, sec-cosec — each pair multiplies to give specific relationships and connects through complementary angle formulas.
  • Complementary angles principle: sin(90° - θ) = cos θ, tan(90° - θ) = cot θ, sec(90° - θ) = cosec θ — this allows conversion between ratios.
  • Pythagorean identities emerge from the theorem a² + b² = c² applied to the unit circle concept, giving three fundamental squared relationships.
  • Trigonometric ratios of standard angles (0°, 30°, 45°, 60°, 90°) must be memorised — they form the basis of almost every numerical problem.
  • Reciprocal relationships: cosec θ = 1/sin θ, sec θ = 1/cos θ, cot θ = 1/tan θ — these allow quick conversion between ratios.
  • Quotient relationships: tan θ = sin θ/cos θ and cot θ = cos θ/sin θ — useful for simplifying complex expressions.

Formulas / Key Facts

The Six Trigonometric Ratios (for angle θ in a right triangle)

RatioFormulaReciprocal
sin θPerpendicular / Hypotenusecosec θ
cos θBase / Hypotenusesec θ
tan θPerpendicular / Basecot θ

Memory aid: "Some People Have Curly Brown Hair Through Proper Brushing" — Sin = P/H, Cos = B/H, Tan = P/B

Standard Angle Values Table

Angle0°30°45°60°90°
sin01/21/√2√3/21
cos1√3/21/√21/20
tan01/√31√3undefined

Pattern for sin: √0/2, √1/2, √2/2, √3/2, √4/2 — just remember the numerator sequence 0, 1, 2, 3, 4 under the root, divided by 2.

Fundamental Identities

  1. sin²θ + cos²θ = 1
  2. 1 + tan²θ = sec²θ
  3. 1 + cot²θ = cosec²θ

Complementary Angle Relationships (θ + φ = 90°)

  • sin(90° - θ) = cos θ
  • cos(90° - θ) = sin θ
  • tan(90° - θ) = cot θ
  • cot(90° - θ) = tan θ
  • sec(90° - θ) = cosec θ
  • cosec(90° - θ) = sec θ

Worked Examples

Example 1: Finding Ratios from Given Information

Problem: If sin θ = 3/5, find cos θ and tan θ.

Solution:

  • Using sin²θ + cos²θ = 1
  • (3/5)² + cos²θ = 1
  • 9/25 + cos²θ = 1
  • cos²θ = 1 - 9/25 = 16/25
  • cos θ = 4/5 (taking positive value for acute angle)
  • tan θ = sin θ / cos θ = (3/5) / (4/5) = 3/4

Example 2: Evaluating Standard Angle Expressions

Problem: Find the value of sin²30° + cos²60° + tan²45°

Solution:

  • sin 30° = 1/2, so sin²30° = 1/4
  • cos 60° = 1/2, so cos²60° = 1/4
  • tan 45° = 1, so tan²45° = 1
  • Sum = 1/4 + 1/4 + 1 = 1/2 + 1 = 3/2

Example 3: Proving an Identity

Problem: Prove that (1 + tan²θ) × cos²θ = 1

Solution:

  • LHS = (1 + tan²θ) × cos²θ
  • Using identity: 1 + tan²θ = sec²θ
  • LHS = sec²θ × cos²θ
  • Since sec θ = 1/cos θ, we have sec²θ = 1/cos²θ
  • LHS = (1/cos²θ) × cos²θ = 1 = RHS
  • Hence proved.

Common Mistakes

  • Confusing perpendicular and base → The perpendicular is always opposite to the angle θ, and base is adjacent to it. Draw the triangle and mark the angle first before identifying sides.
  • Forgetting that tan 90° and sec 90° are undefined → Students often write tan 90° = 1 or some finite value. Remember: division by zero (cos 90° = 0) makes these undefined.
  • Applying Pythagorean identity incorrectly as sin θ + cos θ = 1 → The identity involves squares: sin²θ + cos²θ = 1. The sum sin θ + cos θ can range from 1 to √2 for acute angles.
  • Mixing up complementary angle conversions → sin 60° ≠ cos 60°. Instead, sin 60° = cos 30° (complementary pairs sum to 90°). Always check: does 60° + 30° = 90°?
  • Rationalisation errors with √2 and √3 → When simplifying 1/√2, multiply by √2/√2 to get √2/2. Students often leave irrational numbers in denominators, which may not match answer options.

Quick Reference

  • SOH-CAH-TOA: Sin = Opposite/Hypotenuse, Cos = Adjacent/Hypotenuse, Tan = Opposite/Adjacent
  • sin²θ + cos²θ = 1 is the master identity — the other two derive from dividing this by cos²θ or sin²θ
  • sin and cos of complementary angles swap: sin 40° = cos 50°
  • tan 45° = 1 — the only standard angle where perpendicular equals base
  • For standard angles: sin increases from 0° to 90° while cos decreases — they cross at 45° where both equal 1/√2
  • Quick check: If your answer for a ratio of an acute angle is negative or greater than 1 (for sin/cos), recalculate immediately

Drafted with AI from Shishya's syllabus outline for this exam · Reviewed by a person: not yet · Report an error

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  • Q1 · Trigonometry · MEDIUM

    If sin θ = 3/5, what is the value of cos θ when θ is an acute angle?

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Notes generated on 28 Jun 2026